Please help I need this ASAP!

Have an amazing day :) <br><br> Will give brainlst

Oduvanchick [21]

The correct answer is 120

8 0

3 years ago

Each month, Liz pays $35 to her phone company just to use the phone. Each text she sends costs her an additional $0.05. In March

Firdavs [7]

<h3><u>Answer:</u></h3><h3><u>752 & 617</u></h3><h3 /><h3><u>Explanation:</u></h3><h3><u>So if Liz pays $35 each month just to use the phone, we could subtract 35 from the total bill that month to get the the total cost she spent on text messages.</u></h3><h3 /><h3><u>March:$72.60-$35=$37.60</u></h3><h3><u>April: $65.85-$35=$30.85</u></h3><h3 /><h3><u>We can see that in March Liz spent $37.60 on texts in total and in April she spent $30.85 on texts in total. All we have to do is divide the amount of money she spent on texts( $37.60 & $30.85) by the cost of one text message($0.05) to get the amount of texts she sent that month.</u></h3><h3 /><h3><u>March: $37.60/$0.05=752</u></h3><h3><u>April: $30.85/$0.05=617</u></h3><h3 /><h3><u>Therefore, she sent 752 texts in March and 617 texts in April.</u></h3><h3 /><h3><u>~FrxziteTheLxoser~ I hoped I help you :)</u></h3>

<u>If i helped you please give me brainIIlest!</u>

3 0

3 years ago

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina com 1mx0,8m. Sabendo que ele recortou 2 triângulos, a

Gnom [1K]

Answer:

7190 cm²

Step-by-step explanation:

Para recortar algumas figuras geométricas, um aluno utilizou uma cartolina de 1 m x 0,8m.

Passo 1

Determine a área de todo o papelão

= Temos dimensões = 1mx0,8m

Área = Comprimento × Largura

= 0,8m²

Nós convertemos para cm²

1 m² = 10.000 cm²

0,8m² = x cm²

Multiplicação cruzada

0,8m² × 10.000 cm² / 1 m²

= 8000 cm²

Passo 2

Sabendo que recortou 2 triângulos, ambos com 20cm de base e 30cm de altura

Encontramos a área de um triângulo

= 1/2 × base × altura

= 1/2 × 20 × 30

= 300cm²

Ele cortou 2 triângulos Portanto, o são dos dois triângulos = 300cm² × 2

= 600cm²

etapa 3

Ele também cortou 2 trapézios ambos com bases de 10cm e 20cm e altura de 7cm.

A área de um trapézio =

1/2 (a + b) h

= 1/2 (10cm + 20cm) × 7cm

= 1/2 × 30 × 7

= 105 cm²

Ele cortou dois trapézios, portanto

A área dos dois trapézios do corte = 105cm² × 2

= 210 cm²

Passo 4

A área total do papelão que foi cortado = 600cm² + 210cm²

= 810 cm²

Etapa 5

Determine em cm² quanto de papelão sobrou.

Isso é calculado como:

Área total do papelão - Área total que foi cortada

= 8000 cm² - 810 cm²

= 7190 cm²

5 0

3 years ago

Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25

tino4ka555 [31]

The answer is D. Here is the picture:

5 0

3 years ago

Read 2 more answers

The lengths of pregnancies are normally distributed with a mean of days and a standard deviation of days. a. Find the probabilit

Alik [6]

Answer:

a) The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b) We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In this question:

Mean $\mu$ , standard deviation $\sigma$

a. Find the probability of a pregnancy lasting X days or longer.

The probability of a pregnancy lasting X days or longer is given by 1 subtracted by the p-value of $Z = \frac{X - \mu}{\sigma}$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

b. If the length of pregnancy is in the lowest a%, then the baby is premature. Find the length that separates premature babies from those who are not premature.

We have to find X when Z has a p-value of $\frac{a}{100}$ , and X is given by: $X = \mu - Z\sigma$ , in which $\mu$ is the mean and $\sigma$ is the standard deviation.

8 0

3 years ago