Please help I’m begging you!!

Complete the proofs using the most appropriate method. may require CPCTC.

n200080 [17]

For the first one, you did good. I will just suggest a couple things.

Statement Reason

JK ≅ LM Given

<JKM ≅ < LMK Given (You did both of these steps so well done.)

MK ≅ MK Reflexive Property (Your angle pair is congruent but isn't one of the interior angle of the triangles you are trying to prove.)

ΔJMK ≅ ΔLKM SAS

Problem 2: (You also have a lot of great stuff here.)

Statement Reason

DE ║ FG Given

DE ≅ FG Given

<DEF≅<FGH Given

<EDF≅<GFH Corresponding Angles (You don't need to know that F is the midpoint but you got corresponding angle pair which is correct.)

ΔEDF≅ΔGFH ASA

<DFE≅<FHG CPCTC

3 0

3 years ago

BIG POINT FOR WHOEVER HELPS ME! PLEASE!!!!!Simplify and determine the coefficient of (-2/3X)(3Y).-X)

rewona [7]

You multiply like terms first, which means -2/3x*-x. It becomes 2/3x*3y. The coefficient of x is 2/3. The coefficient of y is 3. You can’t combine them because they are not like terms with the variables.

6 0

3 years ago

Find the approximate circumference of a circle with a diameter of 100 yards.

elixir [45]

Answer:

D. 314 yds

Step-by-step explanation:

Given:

Diameter = 100 yds

Required;

Circumference of the circle

Solution:

Circumference of circle = πd

Plug in the value

Circumference = π × 100

= 314 yds (nearest whole number)

5 0

3 years ago

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2 and increases into quadrant 1. It crosses the y-ax

KIM [24]

Answer:

3

Step-by-step explanation:

f(x)=a*b^x - is a formula of exponential function

As we know the point (x=0; y=3) lies at the function's graph.

So we have to put in formula f(x)=a*b^x x=0 f(x)=y=3

3=a*b^0 (b^0=1) => 3=a*1 => 3=a

6 0

3 years ago

Read 2 more answers

Mr jones is planning to pant grass and place afence in a small area for his dog. The rectagular dimension are 12×15 feet. The gr

goldenfox [79]

Answer:

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572

Step-by-step explanation:

Given as :

The dimension of rectangular field

Length of rectangular field = L = 12 feet

width of rectangular field = w = 15 feet

The cost of grass per square foot = 50 cents = $0.5 ( ∵ 1 cents = $0.01 )

The cost of small fence = $8 per linear foot

Now, According to question

A ) Let The total feet needed for the fence total perimeter = A feet

∵ Perimeter of rectangular field = 2 × Length + 2 × width

Or, A = 2 × L + 2 × w

Or, A = 2 × 12 feet + 2 × 15 feet

Or, A = 24 feet + 30 feet

∴ A = 54 feet

So, The total feet needed for the fence total perimeter = A = 54 feet

B ) Let The total cost of fence = $B

So, The total cost of fence = The cost of small fence × perimeter of fence

i.e B = $8 × 54 feet

∴ B = $432

So,The total cost of fence = B = $432

C) Let the square feet of grass needed foe the total area = C square feet

∵The Area of rectangular fence = Length × width

Or, The square feet of grass needed foe the total area = Area of rectangular fence = L × w

i.e C = 12 feet × 15 feet

Or, C = 180 feet²

So,The square feet of grass needed foe the total area = C = 180 square feet

D) Let The total cost of grass = $D

∵ The cost of grass per square foot = $0.5

So,Total cost of grass = $0.5 × Area of fence

i.e D = $0.5 × 180 feet²

Or, D = $90

So, The Total cost of grass = D = $90

E) Let the total cost of the project = $E

∵Mr. Jones spend additional $50 for tools

So, The total cost of the project = money spent on tools + total cost of fence + Total cost of grass

i.e E = $50 + B + D

Or, E = $50 + $432 + $90

∴ E = $572

So, The total cost of the project = E = $572

Hence,

A) The total feet needed for the fence total perimeter is 54 feet

B) The total cost of fence is $432

C) The square feet of grass needed foe the total area is 180 square feet

D) The total cost of the project is $572 Answer

3 0

3 years ago