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Darya [45]
3 years ago
7

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar

e true? Check all that apply.
7 x + 4 and 3 x + 5 + 4 x minus 1

-When x = 2, both expressions have a value of 18.
-The expressions are only equivalent for x = 4 and x = 6.
-The expressions are only equivalent when evaluated with even values.
-The expressions have equivalent values for any value of x.
-The expressions should have been evaluated with one odd value and one even value.
-When x = 0, the first expression has a value of 4 and the second expression has a value of 5.
-The expressions have equivalent values if x = 8.
Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

When x=2, both expressions have a value of 18.

The expressions have equivalent values for any value of x.

The expressions have equivalent values if x=8

Step-by-step explanation:

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In tests of a computer component, it is found that the mean time between failures is 937 hours. A modification is made which is
VladimirAG [237]

Answer:

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Test Statistics z = 2.65

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

P- value = 0.004025

Step-by-step explanation:

Given that:

Mean \overline x = 960 hours

Sample size n = 36

Mean population \mu = 937

Standard deviation \sigma = 52

Given that the mean  time between failures is 937 hours. The objective is to determine if the mean time between failures is greater than 937 hours

Null hypothesis is \mathbf {H_o: \mu > 937}

Alternative hypothesis is \mathbf {H_a: \mu < 937}

Degree of freedom = n-1

Degree of freedom = 36-1

Degree of freedom = 35

The level of significance ∝ = 0.01

SInce the degree of freedom is 35 and the level of significance ∝ = 0.01;

from t-table t(0.99,35), the critical value = 2.438

The test statistics is :

Z = \dfrac{\overline x - \mu }{\dfrac{\sigma}{\sqrt{n}}}

Z = \dfrac{960-937 }{\dfrac{52}{\sqrt{36}}}

Z = \dfrac{23}{8.66}

Z = 2.65

The decision rule is to reject null hypothesis   if  test statistics is greater than  critical value.

CONCLUSION:

Since test statistics is greater than  critical value; we reject the null hypothesis. Thus, there is sufficient evidence to support the claim that the modified components have a longer mean time between failures.

The P-value can be calculated as follows:

find P(z < - 2.65) from normal distribution tables

= 1 - P (z ≤ 2.65)

= 1 - 0.995975     (using the Excel Function: =NORMDIST(z))

= 0.004025

6 0
3 years ago
The value of the 4 in 429?
iragen [17]

Answer: It is in the Hundreds place

Step-by-step explanation:

429  four is in the hundreds place,2 is in the tens place, and 9 is in the one place.

4 0
3 years ago
James has 24 shirts 18 pants and 16 shoes (pairs) how many combinations of shirt shoes and pants if he wears his favorite shirt(
kodGreya [7K]

multiply pants  & shoes

16 x 18 = 288


5 0
3 years ago
a circular garden has a diameter of 12 feet. what is the best approximation for the circumference of the garden? use 3.14 to app
Nuetrik [128]

Answer:

37.68

Step-by-step explanation:

C(circumference)= 2pi r

If the diameter is 12, the r adius is 6

plug into equation

2(pi)(6)

=12pi

=37.68

3 0
3 years ago
Circle A has been enlarged to create circleA prime . The picture below shows the diameters of both circles.
igomit [66]

Answer:

Step-by-step explanation:

8 0
2 years ago
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