10(the number of tests) divided by 5(the amount of weeks)=2. That is 2 tests every week. 2x7 weeks is 14 tests.
Or this could be a trick question and he could have only had tests for 5 weeks.
Hello!
We know that surface area of a cone = pi(r^2) + pi(rL) where L is the Slant height and R is the Radius and h is Height.
So, 30 is height, and half of 32 is the radius, then we just plug and chug,
An in Short, Your Answer would be 2512, Option "A"
Hope this Helps! :)
Answer:
68% increase and 91% increase
Step-by-step explanation:
220(1+x)=370 -- 220(1+rate increase)=370
1+x=1.68
x=.68
220(1+x)=420 (370+50)=420
1+x=1.909
x=.91
Answer:

<h3><em>Topic </em><em>-</em><em> </em><em>Arithmetic</em><em> </em><em>Progression </em><em>(</em><em> </em><em>AP </em><em>)</em></h3>
- Given - <u>a </u><u>general </u><u>term </u><u>for </u><u>a </u><u>sequence.</u>
- To find - <u>the </u><u>1</u><u>5</u><u>0</u><u>t</u><u>h</u><u> </u><u>term </u><u>of </u><u>the </u><u>given </u><u>sequence</u>
so let's start ~
General term ,
= 3n + 10
let's consider certain values of n to get some information with us which will help us solve the problem further !
let's first consider , n = 1 ! then ,

now , let's consider n = 2

then , let's consider n = 3

hence ,
now we've with us an AP which is as follows -

from this Arithmetic Progression ,
we can know that
a = first term = 13
d = common difference = 16 - 13 = 19 - 16 = <u>3</u>
now ,

hope helpful :D
115 are enrolled in Math, of which 55 are also enrolled in English. So, 115-55, or 60 are enrolled in math alone. 225 are enrolled in English, so 175 are not. Then, 175+60/400=.5875 probability that student is not enrolled in English or is enrolled in math. ☺☺☺☺