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3 years ago

6. When Jim is resting, his beart beats 70 times per minute. When Jim is

Mathematics

1 answer:

Nataly_w [17]3 years ago

8 0

If Jim were jogging for have an hour his heart would beat 4,500 times. 4,500 minus 2,100, the amount of time his heart would beat in half an hour if he was resting, would be 2,400. So Jim's heart beats 2,400 more times when he is jogging for half an hour than it would be if he was resting for half an hour.

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Which ordered pairs are solutions to the inequality 2x-y>1?

RideAnS [48]

Answer:

Any points in the shaded region including (2,-2) and (-3,-8)

Step-by-step explanation:

Convert the line into slope intercept form and graph it.

2x-y > 1 becomes -y>1-2x. Divide both sides by -1 and you get y<2x-1. Graph it with the shaded area on the right and a dashed line.

Any point which falls within the shaded red of the graph is a solution. No points on the line since it is not equal to (its dashed) are solutions. Check the location of your points to verify that they fall within this area.

(-3, -8) ---Yes

(-1, -3) ---No

(0, 5) --- No

(1, 6) --- No

(2, -2) ---Yes

8 0

4 years ago

1. W+ 4 = 16

ExtremeBDS [4]

1. W=16-4=12
2. X=-12-7=-19
3. W=6+15=21
5. y=-2+9=7
6. q=35/7=5

Both questions 4 and 7 aren’t written correctly!!

8 0

3 years ago

Find the perimeter of the following triangle.

pashok25 [27]

Hello!

To find the perimeter of the triangle, we need to find the length of all the sides using the <u>distance formula</u>.

The distance formula is: $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

First, we can find the distance between the points (-3, -1) and (2, -1). The point (-3, -1) can be assigned to $(x_{1},y_{1})$ , and (2, -1) is assigned to $(x_{2},y_{2})$ . Then, substitute the values into the formula.

$d =\sqrt{(2 - (-3))^{2}+ (-1 - (-1))^{2}}$

$d =\sqrt{5^{2}+0^{2}}$

$d =\sqrt{25} = 5$

The distance between the points (-3, -1) and (2, -1) is 5 units.

Secondly, we need to find the distance between the points (2, 3) and (2, -1). Assign those points to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ , then substitute it into the formula.

$d =\sqrt{(2 - 2)^{2}+ (-1 - 3)^{2}}$

$d =\sqrt{0^{2}+(-4)^{2}}$

$d =\sqrt{16} = 4$

The distance between the two points (2, 3) and (2, -1) is 4 units.

Finally, we use the distance formula again to find the distance between the points (-3, -1) and (2, 3). Remember the assign the ordered pairs to $(x_{1},y_{1})$ and $(x_{2},y_{2})$ and substitute!

$d =\sqrt{(2 -(-3))^{2}+ (3 - (-1))^{2}}$