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2 years ago

What is -2x-4y+6x-8y

Mathematics

2 answers:

Nostrana [21]2 years ago

7 0

Answer:

4x - 12y

Step-by-step explanation:

-2x - 4y + 6x - 8y

= 4x - 12y

xenn [34]2 years ago

7 0

-2x-4y+6x-8y

Combine the like terms first

-2x+6x-4y-8y

= 4x-12y

answer:

4x-12y

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55565.87 in scientific notation

mihalych1998 [28]

Answer:

5556587 x 10^-2

6 0

2 years ago

A 13?-foot board is cut into two pieces. The longer piece is 7.5 feet longer than the shorter piece. What is the length of each?

chubhunter [2.5K]

Answer:

The smaller board would be 2.75 feet and the longer one would be 10.25 feet.

Step-by-step explanation:

In order to find this, assume the shorter board is equal to x. Next, we would know that the longer board would be equal to x + 7.5. Using these two assumptions, we can add the lengths together, set equal to 13 and then solve for x.

x + (x + 7.5) = 13

2x + 7.5 = 13

2x = 5.5

x = 2.75

Now that we have the length of the shorter board, we can add 7.5 to it to get the larger one.

2.75 + 7.5 = 10.25

6 0

3 years ago

The points A-1,-9) and K(5,1) are endpoints of a diameter of circle 5. Which equation represents circle S?

Lilit [14]

Answer:

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

$x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}$

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

4 0

3 years ago

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers

Please answer this in two minutes

alisha [4.7K]

Answer:

WX = 7.9

Step-by-step explanation:

By applying tangent rule (law of tan) in the given right triangle WXY.

tan(W) = $\frac{\text{Opposite side}}{\text{Adjacent side}}$