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Naya [18.7K]
3 years ago
5

I though originally the answer was 1/4x+4 but tgats not it please help​

Mathematics
2 answers:
laila [671]3 years ago
6 0

Answer:

what is that

Step-by-step explanation:

me cant see

iogann1982 [59]3 years ago
4 0

Answer:

y = 4x

Step-by-step explanation:

You were close, its positive 4 rather than negative 4.

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NO LINKS!! Use the method of substitution to solve the system. (If there's no solution, enter no solution). Part 11z​
Roman55 [17]

Answer:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

Step-by-step explanation:

Given system of equations:

\begin{cases}y=x^2-9\\y=4x-4\end{cases}

To solve by the method of substitution, substitute the first equation into the second equation and rearrange so that the equation equals zero:

\begin{aligned}x^2-9&=4x-4\\x^2-4x-9&=-4\\x^2-4x-5&=0\end{aligned}

Factor the quadratic:

\begin{aligned}x^2-4x-5&=0\\x^2-5x+x-5&=0\\x(x-5)+1(x-5)&=0\\(x+1)(x-5)&=0\end{aligned}

Apply the <u>zero-product property</u> and solve for x:

\implies x+1=0 \implies x=-1

\implies x-5=0 \implies x=5

Substitute the found values of x into the <u>second equation</u> and solve for y:

\begin{aligned}x=-1 \implies y&=4(-1)-4\\y&=-4-4\\y&=-8\end{aligned}

\begin{aligned}x=5 \implies y&=4(5)-4\\y&=20-4\\y&=16\end{aligned}

Therefore, the solutions are:

(x,y)=\left(\; \boxed{-1,-8} \; \right)\quad \textsf{(smaller $x$-value)}

(x,y)=\left(\; \boxed{5,16} \; \right)\quad \textsf{(larger $x$-value)}

6 0
1 year ago
Read 2 more answers
10.3<br> Problem Solving<br> 33/5 as a whole number
goblinko [34]

Answer:

6 and 3/5

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Given vectors
Bogdan [553]

Answer:

option 2, 3, and 5

Step-by-step explanation:

yuh

7 0
2 years ago
Identify the solution(s) of v2+11v−26=0.
miss Akunina [59]

Answer:

i solved for v and got

v = 2, -13

i hope this helps :]

4 0
3 years ago
What is 0.05 repeating as a fraction ?
grin007 [14]
This is the best I got Require to make 2 equations with the same repeating part and subtract them to eliminate the repeating part.

begin by letting x = 0.5555555................. (1)

To obtain the same repeating part after the decimal point need to multiply by 10

hence 10x = 5.555555........................(2)

It is important to obtain 2 equations in x, where the recurring part after the decimal points are exactly the same.

now subtract (1) from (2) to obtain fraction

(2) - (1) : <span>9x=5⇒x=<span><span>59</span></span></span>

8 0
3 years ago
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