First, determine if the boundary line should be dotted or solid. In this case, it should be dotted because the symbol is less than not less than or equal to. This leaves you with options B or D. Now, to see if it should be shaded up or down, test it by substituting any point, let's say the origin (0,0), to see if that point is a solution to the equation. If it is, you shade that side of the graph, but if it's not, you shade the other side of the graph.
0 is less than (-3/4)(0) + 2
0 is less than 2.
Because 0 is actually less than 2, the statement is correct and you shade below the line
Answer: D
Because the 0.96 is less than 1, it means that the house loses value over the years.
Convert 0.96 to a percent: 0.96 = 96%
100% - 96% = 4%
The house loses 4% of it's value every year.
the system has no solution.
Option C is correct.
Step-by-step explanation:
We need to solve the system of equations by substitution
Putting value of x from eq(2) into eq(1)
As as 0≠4is not true, we cannot find the value of y so the system has no solution.
Option C is correct.
Keywords: System of equations
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Answer:
1/6
Step-by-step explanation:
-1/m
-1/-6
1/6
Answer:
a) 8.13
b) 4.10
Step-by-step explanation:
Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1
In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)
On integrating R'(t)
∫ (2/t+1 + 1/√t+1)dt
In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.
∫ (2/t+1 + 1/√t+1)dt
= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt
= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt
= 2ln(t+1) + 2(t+1)^1/2 + C
= 2ln(t+1) + 2√(t+1) + C
a) For total reactions from t = 1 to t = 12
When t = 1
R(1) = 2ln2 + 2√2
≈ 4.21
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
R(12) - R(1) ≈ 12.34-4.21
≈ 8.13
Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.
b) For total reactions from t = 12 to t = 24
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
When t = 24
R(24) = 2ln25 + 2√25
≈ 16.44
R(12) - R(1) ≈ 16.44-12.34
≈ 4.10
Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10
