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zepelin [54]
3 years ago
11

What is a complex series notation that equals one

Mathematics
2 answers:
seropon [69]3 years ago
7 0

2 + i^2 = 1. also i^4 = 1

3 + i^2 = 2 also 2i^4 = 2

4 + i^2 = 3 also 3i^4 = 3

the complex series has a form Z = a + ib, where a is the real number and ib is the imaginary part.

we know i = √-1 so i^2 = -1 and (i^2)^2 = (-1)^2 = 1. or i^4 = 1.

also,

2 + i^2 = 1. since i^2 = -1, 2 + -1 = 2-1 = 1.

if we want to find 2,

3 + i^2 = 2. since we know i^2 will be -1, set the a value to be 1 more the value you need. for example if you want 3, set a to be 4.

for 3.

first make a to be 1 more than 3 which is 4.

3 = 4 + i^2.

Romashka [77]3 years ago
3 0

we know the complex number has standard form a+ib

Inorder to find our answer ib^2 should.be 1

Ex:-

2-i

2:-

\\ \sf\longmapsto 2+2i^2

  • i^4=1
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Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr
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Answer:

A=73.8\°

B=8.2\°

c=76.3\ units

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)

substitute the given values

c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)

c^{2}=5,823.5738

c=76.3\ units

step 2

Find the measure of angle A

Applying the law of sine

\frac{a}{sin(A)}=\frac{c}{sin(C)}

substitute the given values

\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}

sin(A)=(74)sin(98\°)/76.3

A=arcsin((74)sin(98\°)/76.3)

A=73.8\°

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180\°

substitute the given values

73.8\°+B+98\°=180\°

171.8\°+B=180\°

B=180\°-171.8\°=8.2\°

5 0
3 years ago
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Step-by-step explanation:

A∩B means "A intersection B" which includes all elements that are shared in BOTH sets. This would be the middle crossover section of a Venn diagram.

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