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RUDIKE [14]
3 years ago
5

A 1.8-ounce jar cinnamon costs $4.05. What is the cost per ounce?

Mathematics
2 answers:
Paha777 [63]3 years ago
6 0
$4.05/1.8 oz= $2.25 per oz

Final answer: $2.25 per oz
rodikova [14]3 years ago
3 0

Answer:  The required cost per ounce of cinnamon is $2.25.

Step-by-step explanation:  Given that a 1.8-ounce jar cinnamon costs $4.05.

We are to find the cost per ounce of cinnamon.

We will be using the UNITARY method to solve the problem.

We have

The cost of 1.8 ounces of cinnamon = $4.05.

Therefore, the cost of 1 ounce of cinnamon is given by

\$\dfrac{4.05}{1.8}=\$2.25.

Thus, the required cost per ounce of cinnamon is $2.25.

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24

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This is the same question as before just flipped around

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The expression 3 ( 1 . 5 )^ t models the number of bacteria in a culture as a function of the number of hours since the culture
Masteriza [31]

Answer:

A

Step-by-step explanation:

Given

3(1.5)^{t}

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A bee flew 840 \text{ cm}840 cm840, space, c, m and landed on a flower to collect some pollen. Then the bee flew another 330 \te
alexdok [17]

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<em>The bee traveled 11.7 meters.</em>

Step-by-step explanation:

A bee flew 840 cm first to land on a flower to collect some pollen and then flew another 330 cm to get back to her hive.

For <u>finding the total distance traveled, we need to just add</u> 840 cm and 330 cm.

So, (840+330) cm = 1170 cm

We know that,  1 meter = 100 cm. That means, <u>for converting 'cm' into 'meter' , we need to divide by 100</u>.

Thus,  1170 cm= \frac{1170}{100} meter = 11.7 meter

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5 0
3 years ago
What are the factors of 2x + 3x - 54? Select two options
tiny-mole [99]

Answer:

The answer: The factors are (2x-9) and (x+6).

The Problem:

Factor 2x^2+3x-54

Step-by-step explanation:

So I'm going to do trial factors using the choices to aid me.

Factored form for this problem if it exist will be in the form:

(mx+n)(kx+p).

In general this is what it would look like if we factored any quadratic in terms of x (given the quadratic is not prime but technically you could factor even over the complex numbers).

Let's look at:

(mx+n)(kx+p)

We want to choose k \text{ and } m such that when you multiply them you get 2.  Well those would have to be 2 and 1.

(2x+n)(x+p)

we want to choose n \text{ and } p such that when you multiply them you get -54. Based on the choices we want to get with -9 and 6, or 9 and -6. We don't know the order we want to choose it in either.

For example which of these would work:

(2x-6)(x+9)

(2x+6)(x-9)

(2x-9)(x+6)

(2x+9)(x-6)

We are going to consider only the outer and inner of FOIL since we already know the first times the first is 2x^2 and the last times the last is -54.

Let's test the first one:

(2x-6)(x+9)

Outer:  2x(9)=18x

Inner: -6(x)=-6x

------------------------ADD!

18x-6x=12x

The first choice did not give us the middle term 3x.

Trying the second one would give us the opposite since they are in the same form as previous just the + and - are switched.

Let's look at the third one:

(2x-9)(x+6)

Outer: 2x(6)=12x

Inner: -9(x)=-9x

--------------------------ADD!

12x-9x=3x

This is the winner.

The answer: The factors are (2x-9) and (x+6).

7 0
3 years ago
Read 2 more answers
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