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e-lub [12.9K]
3 years ago
15

Decimal representation of a rational cannot be ?

Mathematics
1 answer:
viktelen [127]3 years ago
7 0
Non-terminating non-repeating
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Time left: 0:48:24<br>Question 11 of 50<br>What are the roots of the quadratic equation<br>x2+3x+2?​
alexgriva [62]

Answer:

-1 & -2

Step-by-step explanation:

x²+3x+2

x²+2x+x+2

(x²+2x)+(x+2)

x(x+2)+1(x+2)

(x+1)(x+2)

6 0
3 years ago
Read 2 more answers
Which expression is equivalent to 64x^3-343
In-s [12.5K]

Answer:

B:  (4x - 7)(16x^2 + 28x + 49)

Step-by-step explanation:

64x^3-343 can be rewritten as 4^3x^3 - 7^3 or (4x)^3 - 7^3.  This is the difference of two cubes.  The appropriate formula for factoring such is

       a^3 - b^3 = (a - b)(a^2 + ab + b^2).  Therefore,

our (4x)^3 - 7^3 = (4x - 7)(16x^2 + 28x + 49).  This is Answer B.

4 0
3 years ago
Play a video game that takes 5 minutes and make at least 12 shots that will result in 200 Virtual Coins per shot. If in one hour
maw [93]

28,000 Virtual coins.

1,728 shots.

7 0
3 years ago
How can you find the lateral area using the perimeter of the base and the height?
DENIUS [597]
You multiply the perimeter of the base by the height of the prism to get the lateral are or. LA=pB*H Lateral Area=perimeter of Base times Height
3 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
DanielleElmas [232]

Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

8 0
3 years ago
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