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e-lub [12.9K]
3 years ago
15

Decimal representation of a rational cannot be ?

Mathematics
1 answer:
viktelen [127]3 years ago
7 0
Non-terminating non-repeating
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Find the dimensions of a rectangle with perimeter 112 m whose area is as large as possible. step 1 if a rectangle has dimensions
Veronika [31]


Please use the solution below:
Let P = perimeter, A = area
As provided above, a = xy and 
We know that the formula to solve for the perimeter of a rectangle is P = 2x + 2y. Using the given 112m, we can solve the perimeter using the formula:
112 = 2x + 2y
56 = x + y

x = 56-y or y = 56-x
Let's solve the perimeter in terms of y using the formula below:
A = (56-y)(y)
Find the derivative of A = 56-y^2 to get the value of y.
dA/dy = 56-2y = 0
y = 56/2
y = 28
To find X, substitute the value of y in the equation x = 56 - y. 
x = 56 - 28
Therefore, x = 28.
We can conclude that the figure is not a rectangle but a square.
7 0
3 years ago
What is5400300 in standard form
choli [55]
Five Millon four thousand and three hundred
7 0
3 years ago
A pentagon has 3 congruent sides and 2 other congruent sides. The perimeter of the pentagon is 36 centimeters. The three long co
Charra [1.4K]

Answer:

B 6 centimeters

Step-by-step explanation:

y = x + 2

2x + 3y = 36

substitute y = x+2  into the second equation

2x + 3 (x+2) = 36

distribute

2x + 3x+ 3*2 = 36

combine like terms

5x+6 = 36

subtract 6 from each side

5x +6-6 = 36 -6

5x = 30

divide by 5

5x/5 = 30/5

x = 6

the short side is x =6

the longer side is

y= x+2

y = 6+2

y =8

6 0
3 years ago
Read 2 more answers
Answer questions 1, 2, 3 and challenge
hjlf
1. find volume
V=LWH
V=25*13*14
V=4550
each covers 1000
how many will cover the whole thing?
we can't put 4 becuase that leaves 550 uncovered
add another


5 is answer (it is too much , but at leas not too little) answer is D




2.
V=LWH
V=6*4*10
V=240

answer is D






3.  count how many are there, don't forget the hidden ones
13 cubes
volume=legnth tiems width times height
cubes so
v=side^3
side=3
3^3=27
13 cubes
13*27=351 in^3


challenge (this is meant to challenge you, not for you to ask people, but I will solve anyway, robbin you of experience)

V=LWH
V=5880
H=30
5880=LW30
divide both sides by 30
196=LW
they have square bases so L=W
196=L^2
sqrt both sides
14=L=W
the side legnth is 14in
4 0
3 years ago
The triangles shown below must be congruent.
viva [34]
I am pretty sure it’s false
6 0
3 years ago
Read 2 more answers
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