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olga nikolaevna [1]
3 years ago
15

2) A snail moving at 3.6 m/h; convert to mm/s

Mathematics
2 answers:
AleksAgata [21]3 years ago
7 0
Answer 60mm/s


Snsndndndndndnddn
jolli1 [7]3 years ago
6 0

Answer:

60mm/s

Step-by-step explanation:

Plz give brianliest and push the thanks button

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Word phrase of 3.5v?
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The product of three point five and a number v
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The graph of g(x) is a transformation of the graph of f(x)=3x 
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There are four types of transformations of an image on a graph: translation, rotation, reflection, and dilation.

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If the image moved across the graph and is in the exact opposite form as it started in (like a mirror,) it is a reflection.

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Just follow the pre-image (f(x)=3x, since it started there,) to the image on your graph (g(x), since it ended there) to find out which transformation it is.
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Step-by-step explanation:

4 0
3 years ago
Scalcet8 4. 2. 26. suppose that 2 ≤ f '(x) ≤ 4 for all values of x. what are the minimum and maximum possible values of f(4) − f
ziro4ka [17]

The minimum value of f(4) - f(1) is <u>6</u>.

The maximum value of f(4) - f(1) is <u>12</u>.

In the question, we are given that, 2 ≤ f'(x) ≤ 4 for all values of x.

Taking the given inequality as (i).

We are asked to find the minimum and maximum possible values of f(4) - f(1).

We multiply (i) by dx throughout, to get:

4dx ≤ f'(x)dx ≤ 5dx.

To find this, we integrate (i) in the definite interval [4, 1] with respect to dx, to get:

\int_{1}^{4}2dx \leq \int_{1}^{4}f'(x)dx \leq \int_{1}^{4}4dx\\\Rightarrow [2x]_{1}^{4} \leq [f(x)]_{1}^{4} \leq [4x]_{1}^{4}\\\Rightarrow 2*4 - 2*1 \leq f(4)-f(1) \leq 4*4 - 4*1\\\Rightarrow 6 \leq f(4) -f(1) \leq 12

Thus, the minimum value of f(4) - f(1) is 6.

The maximum value of f(4) - f(1) is 12.

Learn more about definite integrals at

brainly.com/question/17074932

#SPJ4

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2 years ago
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