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sweet [91]
3 years ago
8

What is the value of x? Enter your answer in the box. x=

Mathematics
2 answers:
AysviL [449]3 years ago
8 0
X = 10^2 - 6^2
x = /64
x = 8
Leya [2.2K]3 years ago
7 0
We can use the Pythagorean theorum.

6^2 + x^2= 10^2

36 + x^2 = 100

x^2 = 64

x = 8
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Mr. Scott’s workroom is a rectangle that measures 25 feet by 27 feet. His woodworking equipment takes up an area of 300 ft squar
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375 because if you do 27x25=675 then I did 675-300=375.
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3 years ago
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Help me pls! I have to get his done.<br>Factorise this!<br>2x^2+5x+3​
MArishka [77]

Hello there!☺

Answer:\boxed{(2x+3)(x+1)}

Explanation:

2x^2+5x+3 Factorized

To factor 2x^2+5x+3, we will have to do it by grouping.

2x^2+5x+3\\(2x+3)(x+1)

(2x+3)(x+1) is your answer.

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2 years ago
Tell me what the slope and y intercept means to you
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A simple linear regression analysis was conducted to predict the Exam 3 score of students in STA 2023 based on their Exam 1 scor
Tju [1.3M]

Answer:

Option 3) The expected Exam 3 score for someone that made a 0 on Exam 1 is a 50.57.            

Step-by-step explanation:

We are given the following in the question:

\hat{y}(x) = 50.57+0.4845x

The above equation is a linear regression equation  to predict the Exam 3 score of students in STA 2023 based on their Exam 1 score.

\hat{y}: The dependent variable, Exam 3 score

x: The independent variable, Exam 1 score

Comparing to general linear equation,

y = mx + c

We get,

m = 0.4845, c = 50.57

where

c is the y - intercept and the score in exam 3 when exam score is 0.

\hat{y}(0) = 50.57+0.4845(0)\\\hat{y}(0) = 50.57

m is the slope and tells us about the rate of change.

When exam 1 grade is increased by 1, we can write,

\hat{y}(x) = 50.57+0.4845x\\\hat{y}(x+1) = 50.57+0.4845(x+1)\\\hat{y}(x+1)-\hat{y}(x) = 50.57+0.4845(x+1)-( 50.57+0.4845x)\\\hat{y}(x+1)-\hat{y}(x) = 0.4845(x+1-x)\\\hat{y}(x+1)-\hat{y}(x) = 0.4845

Thus, the y-intercept for the given equation can be interpreted as

Option 3) The expected Exam 3 score for someone that made a 0 on Exam 1 is a 50.57.

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