Given the circumstances, a triangle can be drawn on a circle where the hypothenuse is 5, the leg going right is 4, and the amount going up is 3 (Try visualizing it). Knowing that tangent is opposite over adjacent of theta, tangent would be 3/4
Product=multiplication
Sum=addition
Difference=subtraction
Quotient=division
Quantity=parentheses
<span>Given
equation = 1/6x – 5 = 1/5x + 2
how can it be set up as linear of equation?
let’s start solving the given equation to show the system of equations:
=> 1/6 x – 5 = y
=> 6y = x – 30
=> 6y – x = -30
=> 1/5 x + 2 = y
=> 5y = x + 10
=> 5y – x = 10
Thus, the system of equation of the given equations are:
=> 6y – x = -30</span><span>
=> 5y – x = 10</span>
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Define x.
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Let the number be x.
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Construct inequality
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7x - 11 ≥ 2
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Add 11 to both sides.
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7x ≥ 13
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Divide by 7 on both sides.
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The problem says that <span>Brandon sights a helicopter above a building that is 200 feet away at an angle of elevation of 30 degrees. So, you can calculate the height asked, by following this procedure:
</span>
Tan(α)=Opposite leg/Adjacent leg
α=30°
Opposite leg=x
Adjacent leg=200 feet
When you substitute these values into the formula above (Tan(α)=Opposite leg/Adjacent leg), you have:
Tan(α)=Opposite leg/Adjacent leg
Tan(30°)=x/200
You must clear "x":
x=200xTan(30°)
Therefore, the value of "x" is:
x=115 feet
<span>
How high above the ground the is the helicopter?
The answer is: 115 feet</span>