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Georgia [21]
3 years ago
11

Geometry! Please help!

Mathematics
2 answers:
Mazyrski [523]3 years ago
8 0

Answer:

4 cm.

Step-by-step explanation:

We have been given that the given composite figure has an area of 136 square cm.

First of all let us find the area of trapezoid by subtracting the area of rectangle from the area of composite figure.

\text{Area of rectangle}=\text{Length*Width}

\text{Area of rectangle}=\text{6 cm*14 cm}

\text{Area of rectangle}=84\text{ cm}^2

So the area of rectangle is 84 square cm.

\text{Area of trapezoid}=136\text{ cm}^2-84\text{ cm}^2

\text{Area of trapezoid}=52\text{ cm}^2

We will use area of trapezoid formula to solve for the height of our given trapezoid.

\text{Area of trapezoid}=\frac{a+b}{2}*h, where a and b represents lengths of parallel bases and h represents height of trapezoid.

Upon substituting our given values in above formula we will get,

52\text{ cm}^2=\frac{\text{12 cm+14 cm}}{2}*h

52\text{ cm}^2=\frac{\text{26 cm}}{2}*h

52\text{ cm}^2=13\text{ cm}*h

Let us divide both sides of our equation by 13 cm.

\frac{52\text{ cm}^2}{13\text{ cm}}=\frac{13\text{ cm}*h}{13\text{ cm}}

4\text{ cm}=h

Therefore, height of our given trapezoid is 4 cm.

Natalija [7]3 years ago
7 0
So the equation for a trapezoid is A= \frac{b_1+b_2}{2} *h , with the b variable being the 2 bases, h variable for height, and the a variable for area. Firstly, we will need to plug in the appropriate numbers into the equation, and it'll look like this:

136= \frac{12+14}{2} *h

Next, we will need to combine 12 and 14, then divide the sum by 2. Your equation should look like this: 136=13*h

Lastly, just divide each side by 13, and your answer should be 10.46=h
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What is the area of a triangle whose vertices are D(3,3), E(3,-1), and F(-2,-5)?
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There is a formula which employs the use of determinants and which helps us calculate the area of a triangle if the vertices are given as (x_1,y_1),(x_2,y_2),(x_3,y_3). The formula is as shown below:

Area=\frac{1}{2}\begin{vmatrix}x_1&y_1&1 \\ x_2&y_2&1\\ x_3&y_3&1\end{vmatrix}

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