Answer:
f(x) = -2 (x + 2)² - 4
Step-by-step explanation:
f(x) = a (x - h)² + k (h , k) is vertex h = -2 k = -4
pass point (-1 , -6) f(x) = -6 and x = -1
-6 = a (-1 - (-2))² + (-4)
-6 = a - 4
a = -2
quadratic function: f(x) = -2 (x + 2)² - 4
Put numbers up and down the X and Y axis showing what the graph values are. (Ex: see picture ) make sure you do it accurately based on what the slope will look like.
Hi there!


We can calculate dy/dx using implicit differentiation:
xy + y² = 6
Differentiate both sides. Remember to use the Product Rule for the "xy" term:
(1)y + x(dy/dx) + 2y(dy/dx) = 0
Move y to the opposite side:
x(dy/dx) + 2y(dy/dx) = -y
Factor out dy/dx:
dy/dx(x + 2y) = -y
Divide both sides by x + 2y:
dy/dx = -y/x + 2y
We need both x and y to find dy/dx, so plug in the given value of x into the original equation:
-1(y) + y² = 6
-y + y² = 6
y² - y - 6 = 0
(y - 3)(y + 2) = 0
Thus, y = -2 and 3.
We can calculate dy/dx at each point:
At y = -2: dy/dx = -(-2) / -1+ 2(-2) = -2/5.
At y = 3: dy/dx = -(3) / -1 + 2(3) = -3/5.
Answer:
r= 3 h = 6 then use 3^2 + 6^2 = l^2
Step-by-step explanation: