Help? i'll mark brainliest if correct

There were 23 bales of hay in the barn sam stacked more bales in the barn today. There are now 68 bales of hay in the barn. How

Deffense [45]

Okay, so you do
$68-23$ <u />
Because the difference will be how much bales of hay Sam stored
and the difference is $45$ <u />

7 0

2 years ago

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A pair of shoes that regularly sells for $45 was discounted by 20% off. What is the sale price

Slav-nsk [51]

It would be 36$ :) :) :) :) :) :)

6 0

3 years ago

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Write an algebraic expression that has three terms. Two of the terms should be variable terms, and one of the terms should be th

andrey2020 [161]

Answer:

<em>Hello.</em>

An expression does not have an equal sign in it. Here are three examples:

2x + 7y + 6

x + 3y - 6

4x/4y x 6 Good luck!

6 0

3 years ago

A police officer claims that the proportion of accidents that occur in the daytime (versus nighttime) at a certain intersection

Roman55 [17]

Answer: -1.78

Step-by-step explanation:

As per given description, we have

Population proportion : $p=0.35$

Sample size : n= 500

Sample proportion : $\hat{p}=\dfrac{156}{500}=0.312$

Test statistic for population proportion :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\=\dfrac{0.312-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{500}}}\\\\=-1.78146747757\ \ \text{(Simplified)}\\\\\approx-1.78$

Hence, the test statistic for this hypothesis test for a proportion= -1.78

3 0

3 years ago

1.Famous basketball player Michael Jordan had a free throw percentage of 0.83. (He made 83% of his free throw shots.) Assume tha

MissTica

Michael Jordan's Freethrow, the population of the 6 countries and the distribution of the uninsured drivers are illustrations of probabilities

<h3>1. Michael Jordan Freethrow</h3>

The given parameter is:

p = 83% -- the percentage of free throws he made

<u>Probability that he misses his 6th throw </u>

The probability that he misses his 6th throw is:

P = P(He made the first 5 throws) * P(He lost the 6th)

This gives

P = (83%)^5 * (1 - 83%)^1

P = 0.0670

<u>Expected number of miss</u>

The expected number till he misses the first free throw is:

E(x) = np

This gives

E(x) = 6 * 83%

E(x) = 4.98

Approximate

E(x) = 5

Hence, the probability that he misses his 6th throw is 0.0670 and the expected number till he misses the first free throw is 5

<h3>2. Country Populations</h3>

The given parameters are:

Average population = 268.35 million

Standard deviation = 370.43 million

<u>The z-scores for the United States, Egypt, and Mexico</u>

This is calculated as:

z = (x - $\mu$ )/ $\sigma$

So, we have:

US = (332 million - 268.35 million)/ 370.43 million

US = 0.17

Egypt = (104 million - 268.35 million)/ 370.43 million

Egypt = -0.44

Mexico = (128 million - 268.35 million)/ 370.43 million

Mexico = -0.38

<u>The countries from the smallest to the largest </u>

By comparing the z-score of the countries, the order of the countries are:

Egypt, Japan, Mexico, Brazil, United States and India

The countries are ranked that way because the higher the z-score, the higher the population

<h3>3. Uninsured drivers</h3>

The given parameter is:

p = 12.6% -- the percentage of uninsured drivers

<u>Probability that exactly 5 drivers of 30 are uninsured</u>

This is calculated as:

P(x) = nCx * p^x * (1 - p)^(n-x)

So, we have:

P(5) = 30C5 * (12.6%)^5 * (1 - 12.6%)^(30-5)

Evaluate the product

P(5) = 0.1561

<u>Probability that the next uninsured driver is the 7th</u>

This is calculated as:

P = P(First 6 are insured) * P(7th is unisured)

This gives

P = (1 - 12.6%)^6 * (12.6%)^1

P = 0.0562

The probability that exactly 5 drivers of 30 are uninsured is 0.1561, and the probability that the next uninsured driver is the 7th is 0.0562