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2 years ago

Help? i'll mark brainliest if correct

Mathematics

1 answer:

Strike441 [17]2 years ago

5 0

Answer:

36,686

Step-by-step explanation:

5.88 x 12 over 10 = 240

240 x 26 = 36,686

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How do i solve this quadratic equation x²+6x+c

Anuta_ua [19.1K]

recall in a perfect square trinomial, the middle term is the tale-tell guy, we know the middle term is the product of 2 and the two other guys without the exponent, so in this case 6x = 2*√x² * √c.

$\bf 6x=2\cdot \sqrt{x^2}\cdot \sqrt{c}\implies 6x=2\sqrt{x^2c}\implies 6x=2x\sqrt{c}\\\\\\\cfrac{6x}{2x}=\sqrt{c}\implies 3=\sqrt{c}\implies 3^2=c\implies 9=c$

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3 years ago

If the farm has 30 chickens and cows, and there are 82 chicken and cow legs all together, then how many chickens and how many co

natima [27]

There would be 11 cows and 19 chickens

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3 years ago

Read 2 more answers

Which graph represents the function f(x)= -2^x - 1

MAXImum [283]

Answer:

the first graph does////=//

4 0

3 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

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3 years ago

A survey was conducted to find out how much time people have to spend commuting to work. The sample means for two samples are 71

Lorico [155]

Answer:

E: None of the above

Step-by-step explanation:

Hello!

The objective is to find out how much time it takes people to commute to work.

Two samples where taken and two hypothesis tests where made:

One:

Sample mean 71 min; p-value: 0.03

Two:

Sample mean 72 min; p-value: 0.06

You have to choose from the options, a possible pair of hypotheses used for these two tests.

The parameter of the study is the population mean μ.

In the statistic hypotheses, the parameters are given either a known population value or a suspected value. So all options including sample values are wrong.

As said before the objective of the survey is to "determine how much time people spend commuting to work" in other words, whether or not the population mean is equal to a certain value.

H₀: μ = μ₀

H₁: μ = μ₀

Where μ₀ represents the theoretical value of the population mean. As you can say the hypotheses pair is two-tailed, not one-tailed.

Then the correct answer is E: None of the above

I hope this helps!

7 0

3 years ago