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svet-max [94.6K]
3 years ago
9

Luke can buy bottles of water in packages of 6 for $15.24 or in packages of 4 for $11.16. How much money does he save by buying

48 bottles of water at the better price?
Mathematics
1 answer:
creativ13 [48]3 years ago
6 0

Answer:

6\ for\ \$15.24\ is\ better\ price\\\\Total\ saving=\$12

Step-by-step explanation:

Cost at the rate 6 for $15.24:

Cost of 6 bottles=\$15.24

Cost of 1 bottle=\$\frac{15.24}{6}

Cost of 48 bottles=\frac{15.24}{6}\times 48=15.24\times 8=\$121.92

Cost at the rate 4 for $11.16:

Cost of 4 bottles=\$11.16

Cost of 1 bottle=\frac{11.16}{4}

Cost of 48 bottles=\frac{11.16}{4}\times 48=11.16\times 12=\$133.92

Hence 6\ bottles\ for\ 15.24 is less expensive.

Total saving=133.92-121.92=\$12

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A bag contains pennies, nickels, nickels, and nickels. There are 50 coins in total. Of the coins, 14% are pennies and 34% are di
Alborosie

answer:

8 pennies,16 dimes,13 nickels,13 quarters

Step-by-step explanation:

total number of coins = 50

16% are pennies

16% of 50

16/100 x 50=(16x50)/100=800/100=8

Pennies = 8

32% are dimes

32% of 50

32/100 x 50=(32x50)/100=1600/100=16

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5 more nickels than pennies

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8 0
2 years ago
Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x
Svet_ta [14]

Answer:

A^{'} = {1,3,5,7,9,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = {1,2,3,4,5}

D^{'} = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set  C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

A^{'} = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

A^{'} = {1,3,5,7,9,....}

B^{'} = U-B =  {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

B^{'} = {1,2,4,5,7,8,10,11,13,14......}

C^{'} = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

C^{'} = {1,2,3,4,5}

D^{'} = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

D^{'} = {10,11,12,13,14,15,......}

8 0
2 years ago
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