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Gala2k [10]
2 years ago
11

Bill plans to buy school supplies and the following equation represents what he bought.

Mathematics
2 answers:
Lena [83]2 years ago
8 0

Answer:

1. 8

Explanation: 5x + 20(.50)=50

5x + 10=50. Now do 50-10 to get 40. So,

5x=40. Now divide 40/5 to get 8.

2. .5

5(8) + 20x=50. Now do 5*8

40 + 20x=50. Now, 50-40 to get

20x=10. And divide 10/20 to get .5

iren2701 [21]2 years ago
6 0

Answer:

1. x = 8

2. y = 1/2

Step-by-step explanation:

1. Plug the function

5x + 20(0.50) = 50

= 5x + 10 = 50

Subtract 10 from both side

= 5x = 40

Divide 5 on both sides

= x = 8

2. Plug in the function

5(8) + 20y = 50

= 40 + 20y = 50

Subtract 40 on both sides

= 20y = 10

Divide 20 both sides

= y = 10/20 | 1/2

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(p^2) + 3p - 18

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77

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If y varies directly with x and y=2 when x=15. Find x when y=8.
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3 years ago
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The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.9 and a standard deviation of
labwork [276]

Answer:

A) Approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%

Step-by-step explanation:

We are given;

mean;μ = 247.9

standard deviation;σ = 64.7

A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3.

Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.

While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Thus, approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.

53.8 and 442.0 represents 3 standard deviations from the mean.

Let's confirm that.

Since mean;μ = 247.9

standard deviation;σ = 64.7 ;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

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3 years ago
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