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tatiyna
2 years ago
14

Approximately what percentage of apple diameters is greater than the 66th percentile? 21. A. 3.4% B. 17% C. 66% D. 34%

Mathematics
1 answer:
astraxan [27]2 years ago
5 0

Answer:

The correct option is D) 34%.

Step-by-step explanation:

Consider the provided information.

If it is given that you scored in the 66th percentile, that means you scored "as well as or better than" 66% of the group.

Here it is given that 66th percentile that means 66% of the data located below the 66th percentile.

That means 100%-66% = 34% of the data located above the 66th percentile,

Thus, the approximately 34% percentage of apple diameters is greater than the 66th percentile.

Therefore, the correct option is D) 34%.

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D.

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3 years ago
HELP ASAP Solve for x. Show or explain your work.
irinina [24]

Answer:

x=4.5

Step-by-step explanation:

From AAA, both triangles in this figure are similar. Therefore, we can set up the following proportion:

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2 years ago
What is the value of the variables?
iren [92.7K]

Answer:

x=9 and w=12

Step-by-step explanation:

To solve for w and x, create proportions between the two similar triangles.

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where Big represents the bigger triangle an little represents the smaller triangle.

\frac{8}{16}=\frac{w}{12+w}

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8(12+w)=16(w)

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6 0
3 years ago
1. Write the equation in standard form. Identify the important features of the graph:
NeTakaya

Answer:

  1. (x-4.5)^2 +(y +5)^2 = 30.25
  2. x = (1/8)y^2 +(1/2)y +(1/2)
  3. y^2/36 -x^2/64 = 1
  4. x^2/16 +y^2/25 = 1

Step-by-step explanation:

1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.

  (x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15

  (x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form

Important features: center = (4.5, -5); radius = 5.5.

__

2. To put this in the form x=f(y), we need to add 8x, then divide by 8.

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Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.

__

3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:

  y^2/36 -x^2/64 = 1

__

4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.

  x^2/16 +b^2/25 = 1

_____

The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.

6 0
2 years ago
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