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Verizon [17]
3 years ago
6

Please help! Need to turn it in by tomorrow!

Mathematics
2 answers:
Volgvan3 years ago
7 0

Answer:

for some reason I cant see the picture

can you send it again so I can answer

Step-by-step explanation:

Gelneren [198K]3 years ago
3 0

Answer:

A,D

Step-by-step explanation:

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The length of a rectangle is 4.9 cm more than 4 times the width. If the perimeter of the rectangle is 88.8 cm, what
Kamila [148]

Answer:

24.9 by 5.

Step-by-step explanation:

4 0
3 years ago
A sorority has 38 members, 28 of whom are full members and 10 are pledges. Two persons are selected at random from the membershi
butalik [34]

Answer:

(a) 185/703

(b) 518/703

(c) 45/703

(d) 140/703

(e) 140/703

(f) 378/703

(g) 185/703

Step-by-step explanation:

Let the event of pledge member be P and event of full member be F

(a)If the first is a pledge, then the second is either a pledge or a member.

required Probabability = [P n (PUF)]

= Pr(PnP) U Pr (PnF)

= 10/38 × 9/37 + 10/38 × 28/38

= 90/1406 + 289/1406 = 370/1406

= 185/703

(b) if the person selected is not a pledge then the person is a full member and the second is either a full member or pledge

The required probability = Fn(FUP) =Pr (FnP) U Pr(FnF)

= 28/38 × 10/37 + 28/38 × 27/37

= 280/1406 + 756/140 = 1036/1406

= 518/703

(c) probability required= Pr(P/P) = Pr(PnP) = 10/38 × 9/37

= 90/1406

= 45/703

(d) Probability required = Pr(F/P)

= Pr(P) nPr(F) = 10/38 × 28/37

= 280/1406

= 140/703

(e) Probability required = Pr(P/F)

= Pr(F) n Pr(P)

= 28/38 × 10/37 =280/1406

=140/704

(f) Probability required = Pr (FnF)

= Pr(F) n Pr(F)

= 28/38 × 27/37= 756/1406

= 378/703

(g) it is the either the first person is a pledge member or a full member

Probability required = Pr[(PnP) U (FnP)]

= Pr(PnP) + Pr(FnP)

= 10/38 × 9/37 + 28/38 × 10/37

= 90/1406 + 280/1406

= 370/1406

= 185/703

(h) see attachment.

8 0
3 years ago
How do you find the value of X? Isosceles and Equilateral Traingle
Svetradugi [14.3K]
Did they give values for the letters??
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3 years ago
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A mule dear can 1/4 of a mile in 25 seconds. At this rate, what expression can be used to determine how fast a mule deer runs in
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We have to find how many seconds are in one hour.
There are 60 seconds in one minute, with 60 minutes in every hour.
60×60=3600
Now, see how many 25 seconds are in 3600 seconds.
3600÷25= 144
Now, we can multiply 144 by 14 or .25 since we are trying to find per hour.
144×.25= 36
36h
H being the hours you're trying to find. It runs 36 miles per hour.
5 0
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Deirdre is factoring the polynomial x2 + 2x – 24. Which combination can she use to replace the middle term, 2x?
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to replace 2x we need +6x-4x

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3 years ago
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