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LUCKY_DIMON [66]
3 years ago
13

HELP ME PLEASE!!!!!!!!!!!!

Mathematics
1 answer:
Aleksandr [31]3 years ago
4 0

Answer:

Question 6: C or 1/3

3 toppings times 2 flavors=6 types in all

you can get chocolate or vanilla yogurt with sprinkles. This gives u 2/6 or 1/3

Question 11: 2/9 + x = 1

x= 7/9

Step-by-step explanation:

Question 11: 2/9 + x = 1

x= 7/9

Question 6: 3 toppings times 2 flavors=6 types in all

you can get chocolate or vanilla yogurt with sprinkles. This gives u 2/6 or 1/3

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What is 11.375 in faction
Anton [14]
11 3/8 would be the simplified version and 91/8 would be the other way.
6 0
4 years ago
Read 2 more answers
Please can someone help me with this question
sasho [114]

<em>Answer:</em>

<em>r = -</em>\frac{6a}{1-5m^2}<em />

<em>Step-by-step explanation:</em>

<em>Rewrite the equation as </em>\sqrt{x} 6a+r/5r<em>  = m</em>

<em>Remove the radical on the left side of the equation by squaring both sides of the equation.</em>

<em>(</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> = m^2</em>

<em>Then, you simplify each of the equation. </em>

<em>Rewrite: (</em>\sqrt{\frac{6a+r}{5r} )^{2}<em> as </em>\frac{6a+r}{5r} = m^{2}<em />

<em>Remove any parentheses if needed.</em>

<em>Solve for r. </em>

<em>Multiply each term by r and simplify."</em>

<em>Multiply both sides of the equation by  5.</em>

<em>6a+r= m^2r⋅(5)</em>

<em>Remove parentheses.</em>

<em>Move 5   to the left of (m ^2)  r </em>

<em>6a+r=5m^2)r</em>

<em>Subtract  5m^2)r  from both sides of the equation.</em>

<em>6a+r-5m^2)r=0</em>

<em>Subtract  6a  from both sides of the equation.</em>

<em>r-5m^2)r=-6a</em>

<em>Factor  r out of  r-5m^2)r  </em>

<em>r(1-5m^2)=-6a</em>

Divide each term by 1-5m^2 and simplify.

r = - \frac{6a}{1-5m^2}

There you go, hope this helps!

4 0
4 years ago
At the grocery store there are two different options for buying Coke. You can buy a 12 pack for $5.49 or an 18 pack for $8.59. W
baherus [9]

Step-by-step explanation:

The 18 Pack why is because it has more Coke than the other one and it is less expensive than the other one if it had 18.

3 0
3 years ago
Find the least number which must be added to 6203 to obtain a perfect square.
andrey2020 [161]

Answer:

79

Step-by-step explanation:

       78

         ---------

7 |       62 03 

          49

         ----------

148 |   13 03

          11 84

         -----------

            19

         -----------

78^2 = 6084.

We observe that 78^2 < 6203.

79^2 = 6241.

We observe that 79^2 > 6203.

Hence the number to be added to 6203 is 6241 - 6203 = 38.

6203 + 38 = 3241

                  = 79 * 79

                  = 79.

Therefore 38 should be added to 6203 to obtain a perfect square.

5 0
3 years ago
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