We are required to find the cosine and tangent of 60°. Here we use an equilateral triangle whose side is 2 units, the height of the triangle by Pythagorean theorem will be √3 units, the base of the right angle triangle formed by bisection of the base will be 1 unit.
thus:
tan θ=opposite /adjacent
opposite= √3
adjacent=1
hence:
tan 60=√3/1=√3
cos θ=adjacent/ hypotenuse
adjacent=1
hypotenuse=2
thus
cos 60=1/2
Answer:
3/12 is less than 3/4
Step-by-step explanation:
3/12 is the same as 1/4, which is 0.25
3/4 is 0.75
A11 1 * [ (2*5) - (5*2)] = 0
a12 = -4 *(5*5) - 2*1) = 23*-4 = -92
a13 = 4 * (5*5) - (1*2) = 23 * 4 = 92
a21 = 0
a22 = 2 * (5-4) = 2
a23 = -2 * (5-4) - -2
a31 = 0
a32 = -5*(2-20) = 90
a33 = 5 * (2-10) = -90
Adding these gives zero
Answer is B:- 0
Answer:
add 2x to both sides
Step-by-step explanation:
-x+2y=-10
2y=x-10
y=1/2x-5
Answer:
We validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)
Step-by-step explanation:
Given
A (−1, 4)→ A' (3, 3)
Here:
- A(-1, 4) is the original point
- A'(3, 3) is the image of A
We need to determine which translation operation brings the coordinates of the image A'(3, 3).
If we closely observe the coordinates of the image A' (3, 3), it is clear the image coordinates can be determined by adding 4 units to the x-coordinate and subtracting 1 unit to the y-coordinate.
Thue, the rule of the translation will be:
A(x, y) → A' (x+4, y-1)
Let us check whether this translation rule validates the image coordinates.
A (x, y) → A' (x+4, y-1)
Given that A(-1, 4), so
A (-1, 4) → A' (-1+4, 4-1) = A' (3, 3)
Therefore, we validate that the formula to determine the translation of the point to its image will be:
A (x, y) → A' (x+4, y-1)