Question

If you roll two six-sided dice, what is the probability that at least one dies shows a 5 ?

Answer 1

Answer:

$\frac{11}{36} = 0.3056$ probability that at least one dies shows a 5.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Each dice:

6 sides, one of which is 5.

So 6-1/6 = 5/6 probability of rolling a 5.

Probability of not rolling a five in two rolls:

(5/6)^2 = 25/36

Probability of rolling a five in at least one of the rolls:

$p = 1 - \frac{25}{36} = \frac{36}{36} - \frac{25}{36} = \frac{11}{36} = 0.3056$

$\frac{11}{36} = 0.3056$ probability that at least one dies shows a 5.