Answer:
Well, these simulation are based on the statistics (lognormal-distributed PE, χ²-distributed s²). If you believe that only the ‘gold-standard’ of subject-simulations are valid, we can misuse the function sampleN.scABEL.sdsims() – only for the 3- and 4-period full replicates and the partial replicate:
# define a reg_const where all scaling conditions are ‘switched off’
abe <- reg_const("USER", r_const = NA, CVswitch = Inf,
CVcap = Inf, pe_constr = FALSE)
CV <- 0.4
2x2x4 0.05 0.4 0.4 0.95 0.8 1.25 34 0.819161 0.8
Since the sample sizes obtained by all simulations match the exact method, we can be confident that it is correct. As usual with a higher number of simulations power gets closer to the exact value.
Step-by-step explanation:
Answer:
75 bottles/1 minute
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
The arc length is (2)(pi)(27)(40/360)=6pi.
So, k=6.
I’m pretty sure the answer is D
The given equation does not have any solution.
For given question,
We have been given an equation −5a + 5a + 9 = 8
We know that the like terms are those terms which have same variable to the same power.
Combine Like terms;
0 + 9 = 8
9 = 8
⇒ which is False.
This statement is false for any values of x
Therefore, the given equation does not have any solution.
Learn more about the solution of equation here:
brainly.com/question/545403
#SPJ4