If p = .8 and n = 50, then we can conclude that the sampling distribution of pˆ is approximately a normal distribution
1 answer:
Answer:
Yes we can conclude.
Step-by-step explanation:
The sampling distribution of can be approximated as a Normal Distribution only if:
np and nq are both equal to or greater than 10. i.e.
- np ≥ 10
- nq ≥ 10
Both of these conditions must be met in order to approximate the sampling distribution of as Normal Distribution.
From the given data:
n = 50
p = 0.80
q = 1 - p = 1 - 0.80 = 0.20
np = 50(0.80) = 40
nq = 50(0.20) = 10
This means the conditions that np and nq must be equal to or greater than 10 is being satisfied. So, we can conclude that the sampling distribution of pˆ is approximately a normal distribution
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Step-by-step explanation:
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Answer:
Mean: 169.4
Median: 171
Mode: 181
Step-by-step explanation:
I first sorted the numbers by value, least to greatest.
145 147 153 153 167 170 170 172 181 181 181 182 185 185
We can see that 181 occurs the most, 3 times, so it's the mode.
The median of this set will be the middle number(s).
When we take away 6 numbers from both sides we are left with 170 and 172, and the mean of these two numbers is 171. So the median is 171.
We can add all the numbers and divide by 14 to get the mean.
Hope this helped!