The height of the isosceles triangle is 8.49 inches.
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How to find the height of the triangle?</h3>
Here we have a triangle such that two of the sides measure 9 inches, and the base measures 6 inches.
So this is an isosceles triangle.
We can divide the isosceles triangle into two smaller right triangles, such that the side that measures 9 inches is the hypotenuse, the base is 3 inches, and the height of the isosceles triangle is the other cathetus.
By Pythagorean's theorem, we can write:
(9in)^2 = (3 in)^2 + h^2
Where h is the height that we are trying to find.
Solving that for h we get:
h = √( (9 in)^2 - (3in)^2) = 8.49 inches.
We conclude that the height of the isosceles triangle is 8.49 inches.
If you want to learn more about triangles:
brainly.com/question/2217700
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Answer:
Step-by-step explanation:
2x² divide all the three terms so G.C.F.=2x²
11 9/10 First you have to add 10 3/5 and 12 1/2. You get 22 11/10. That is an improper fraction. There are one 10 in 11. So you add 1 1/10 to 22. You get 23 1/10. Now you have to subtract 23 1/10 and 35. You get 11 9/10
Answer:
Is there a choices?
Step-by-step explanation:
