Answer:
Yes, if you want to be undetected.
Explanation:
It is vital to always use a command that will ensure that one's activity is undetected. This is one of the important rules of corporate organizations to keep their data and activities safe and secure. The commend provided is a useful tool for detective works especially the activities of criminals and hackers. Therefore, if the admin wants to be undetected, the command should not be used.
Answer:
Explanation:
The objective of this task is to compute a program that involves the usage of Python code to save the data to MongoDB and to query the database.
Due to the error that occur which makes me to be unable to submit this answer, I've created a word document instead and the attached file can be found below.
Thanks!
yes
Explanation:
because it has more things
The answer is a) It improves upon the two-phased commit by requiring that locks be acquired at the start of a transaction.
Reason: The 3PC is an extension or you can say developed from 2PC that avoids blocking of an operation. It just ensures that first n sites have intended to commit a transaction that means it acquires commits or locks before the start of any transaction to avoid any blocking.
Option b) is wrong as it does not allow coordination, it just let all the other sites do their transaction if any other site is blocked, so no coordination is there between sites that they will wait till their coordinator is corrected.
Option c) is wrong as lock operations are shared between other connections as when their coordinator fails, the new coordinator agrees to the old coordinator that they had shared locks before and they can start their transaction.
Option d) is wrong as option a) is correct.
If you like the answer, please upvote.
The program is an illustration of loops.
Loops are used to perform repetitive and iterative operations.
The program in Python where comments are used to explain each line is as follows:
#This intializes the list
nums = [5,4,4,2,1]
#This gets the length of the list
size = len(nums)
#This iterates through the list
for i in range(size):
#The following if condition determines the repeating number
if nums[abs(nums[i])-1] > 0:
nums[abs(nums[i])-1] = -nums[abs(nums[i])-1]
else:
repeating = abs(nums[i])
#The following if condition determines the missing number
if nums[i]>0:
missing = i + 1
#This calculates and prints the sum of the missing and the repeating numbers
print(repeating+missing)
Read more about similar programs at:
brainly.com/question/13549861
