Answer:
0.01 second ; 0.008 seconds; 800 seconds
Explanation:
Given that:
Sending rate = 1000 bps
Rate of 1000 bps means that data is sent at a rate of 1000 bits per second
Hence, to send out 10 bits
1000 bits = 1 second
10 bits = x
1000x = 10
x = 10 / 1000
x = 0.01 second
2.)
A single character 8 - bits
1000 bits = 1 second
8 bits = (8 / 1000) seconds
= 0.008 seconds
3.)
100,000 characters = (8 * 100,000) = 800,000
1000 bits = 1 second
800,000 bits = (800,000 / 1000)
= 800 seconds
The publisher tab in the application control allows you to manage the various certificates that are used to sign to binaries. Publisher allow executables of a particular vendor, signed by a security certificate issued
to the vendor by a Certificate Authority. Also, all applications and binary files either added
to or modified on an endpoint that are signed by the certificate are automatically added to
the whitelist.
Answer:
Have a great day, Here is the answer to your question:
It will take around 18 seconds
Explanation:
So in principle 1GB of data to be uploaded running at peak speed is suggested to take around 18 seconds but in fact, DCD test results show USB 2.0 takes 3 minutes 18 seconds to complete a 1GB switch. Whereas USB 3.0 can accommodate up to 5gbps of data transferred-more than 10 times faster than its predecessor.
Answer:
The answer is "Option D".
Explanation:
Binary search is also an efficient mechanism for only a sorted item list. It separates the element into one half of the checklist repeatedly, till you have narrowed it down to the only single place.
In this search, the number of comparisons is much more efficient than in the series to use the binary search approach, the items also should be shown, that's why the last choice is correct.
