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nadezda [96]
3 years ago
13

you are packing a mobile phone containing a lithium ion battery and you get a prompt on the screen to put a lithium ion label on

the box. You have run out of such labels and have only lithium metal labels left. what should you do?
Computers and Technology
1 answer:
ss7ja [257]3 years ago
8 0

Answer:

<u>Do not use such labels because they may be misleading and are unethical.</u>

Explanation:

Note, there is a<u> big difference in design</u> between the two terms or labels. Lithium metal batteries are <u>non-rechargeable batteries.</u> In other words, they cannot be recharged after they run down. For example, most <em>watches, calculators, or car keys are made of </em>lithium metal batteries.

While Lithium-ion batteries (or Li-ion batteries) are <u>rechargeable batteries</u> , and they are commonly used by<em> mobile phones, laptops, and other gadgets.</em>

<em>Therefore, </em>with such differences in mind, it may be very misleading when someone in possession of the mobile phone sees the lithium metal labels; then thinks the battery is non-rechargeable.

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(1) Prompt the user for a string that contains two strings separated by a comma. (1 pt) Examples of strings that can be accepted
denis-greek [22]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <string.h>

#include <stdlib.h>

#define MAX_LIMIT 50

int checkComma(char *input)

{

int flag = 0;

for(int i = 0; i < strlen(input); i++)

{

if(input[i] == ',')

{

flag = 1;

break;

}

}

return flag;

}

int main(void)

{

char input[MAX_LIMIT];

char *words[2];

char delim[] = ", ";

printf("\n");

do

{

printf("Enter input string: ");

fgets(input, MAX_LIMIT, stdin);

size_t ln = strlen(input) - 1;

if (*input && input[ln] == '\n')

input[ln] = '\0';

if(strcmp(input, "q") == 0)

{

printf("Thank you...Exiting\n\n");

exit(1);

}

else

{

if(checkComma(input) == 0)

{

printf("No comma in string.\n\n");

}

else

{

char *ptr = strtok(input, delim);

int count = 0;

while(ptr != NULL)

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words[count++] = ptr;

ptr = strtok(NULL, delim);

}

printf("First word: %s\n", words[0]);

printf("Second word: %s\n\n", words[1]);

}

}

}while(strcmp(input, "q") != 0);

return 0;

}

Kindly check the attached image below for the output.

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