We will use the Binomial probability formula to find the answer
The formula is given by ⁿCₓ (p)ˣ (1-p)ⁿ-ˣ
We have
n, the number of trial = 16
x, the sample we aim to try = 7
p, the probability of success = 0.5
Substitute these values into the formula
P(7) = ¹⁶C₇ (0.5)⁷ (1-0.5)¹⁶⁻⁷
P(7) = 0.1746 (rounded to four decimal places)
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).
For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.
Rinse and repeat question 12 for question 13
3x + 2y = 10 ....multiply by -4
12x + 5y = 25
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-12x - 8y = -40 (result of multiplying by -4)
12x + 5y = 25
------------------add
-3y = - 15
y = -15/-3
y = 5
3x + 2y = 10
3x + 2(5) = 10
3x + 10 = 10
3x = 10 - 10
3x = 0
x = 0
solution is (0,5)
Answer:
greater than (>)
Step-by-step explanation:
4/25=0.16
0.9>0.16
I'm pretty sure that the answer would be 11.
