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navik [9.2K]
3 years ago
14

Steve works two different jobs for a total of 60 hours every Monday through Friday schedule is the same each day and he works th

ree hours a day at his first job how many hours a day does he work at his second job
Mathematics
1 answer:
Semenov [28]3 years ago
4 0

Answer:

Step-by-step explanation:

Steve works:

- 60 hour per week = 12 hours per day (60/5)

- first job: 3 hours per day = 15 hours per week

- x = second job hours per day

equitation:

1st option to calculate:

12 (total hours per day) = 3 (hours per day on first job) + X

9 = X

2nd option to calculate:

60(total hours per week) = 15 (3 hours per day x 5) + x

45 = x

you need to divide 45 / 5 to get the daily hours which is 9

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The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
A random sample of eight drivers insured with a company and having similar auto insurance policies was selected. The following t
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I don’t know they answer I’m really sorry
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3 years ago
Pls help!
lozanna [386]

Answer:

Which formula should be used to calculate the variance?  C

What is the variance? 58.5

5 0
3 years ago
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I neeeeeeed Help please!
pochemuha

Answer:

i ask your teacher

Step-by-step explanation:

ask your teacher instead of asking for answers

4 0
3 years ago
Please, I need your help!! I will mark correct answer as brainliest.<br>​
Marizza181 [45]

Answer:

3, -3, 0

Step-by-step explanation:

The exlcusions of x are where the denominator =0

So we can write the following equations

x²-9=0

and

5x=0

Let's solve the first one

x²-9=0

x²=9

x= ±3

and

5x=0

x=0

Therefore x cannot equal 3, -3, 0

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2 years ago
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