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xxMikexx [17]
3 years ago
11

Predict whether the bond between each pair of atoms will be no polar convalent, polar covalent or ionic

Chemistry
1 answer:
bekas [8.4K]3 years ago
7 0
Yes sir I’m not sure why what I said so yes sir I’m not gonna go to the bathroom I’m just gonna go home I’m gonna be there in about a week or two I don’t uueiueyey
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Casi todos los días usamos el hervidor para calentar el agua con el que hacemos el té o cocinamos los alimentos. Sin embargo, mu
Maru [420]

Answer:

si de si es cierto mi id de freefire. 2301818073

3 0
3 years ago
Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where need
gregori [183]

Answer:

Explanation:

Edit the reaction by drawing all steps in the appropriate boxes and connecting them with reaction arrows. Add charges where needed. Electron flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical.

7 0
3 years ago
Determine the Eo for a Cu-Pb Voltaic Cell
blagie [28]

Answer:

The standard cell potential (E₀) for a Cu-Pb voltaic cell is +0.215V

The experiment is used to determine the standard electrode potential of the Cu-Pb Voltaic cell.

Explanation:

A Voltaic cell is one in which electric energy is produced as a result of the difference in electric potential between two electrodes in chemical solutions that are usually connected by a salt bridge.  

In a voltaic cell, the anode electrode is where oxidation (loss of electrons) occurs while reduction (gain of electrons) occurs at the cathode electrode.

The standard cell potential (E₀) is the difference between the potential of the cathode and anode at standard conditions, that is, at standard temperature, pressure and concentration.  

It is usually expressed as

E₀ = E₀cell (cathode) - E₀cell (anode)

From the given question, the half cell equations are :

Cu(s) - 2e ⇒ Cu²⁺. with  oxidation reaction occuring at the anode  

Pb²⁺  + 2e ⇒ Pb (s).  with reduction reaction occuring at the cathode

Meaning that the solid copper electrode is oxidised by losing two electrons which are gained by the Pb²⁺ ions which are subsequently reduced to solid lead at the other electrode.  

Each half cell reaction has a standard electric potential  (recall that the standard electric potential is the potential at standard conditions, that is, at standard temperature, pressure and concentrations.

)

The overall voltaic cell equation is given as:

Cu(s) I Cu²⁺(aq) II Pb²⁺ (aq) I Pb(s)

The standard cell potential E₀ is obtained by

:

E₀ = E₀cell (cathode) - E₀cell (anode)

At standard conditions, E₀ (Cu(s) ⇒ Cu²⁺  + 2e)  = - 0.340V

                       E₀ (Pb²⁺ + 2e ⇒ Pb(s) = - 0.125V

Therefore, the standard cell potential for a Cu-Pb voltaic cell is,

E₀ = -0.125V - (-0.340V)

  = -0.125V + 0.340V

  = +0.215V

4 0
3 years ago
A sample of sodium reacts completely with 0.284 kg of chlorine, forming 468 g of sodium chloride. What mass of sodium reacted?
Verizon [17]

Answer:

mass of sodium reacted is 184.1 g

Explanation:

  • Na + Cl → NaCl

mass Na = X = ?

∴ mass NaCl = 468 g

∴ mass Cl = 0.248 g

∴ molar mass NaCl = 58.44 g/mol

∴ atomic mass Cl = 35.453 a.m.u

∴ atomic mass Na = 22.989 a.m.u

⇒ moles Na = (X gNa)*(mol Na/22.989 g) = X/22.989 mol Na

⇒ mass NaCl = (X/22.989 mol Na)*(mol NaCl/mol Na)*(58.44 gNaCl/mol NaCl) = 468 g NaCl

clearing "X":

⇒ ((58.44)(X))/(22.989) = 468 g

⇒ X = 184.1 g = mass Na reacted

4 0
3 years ago
1. The following are statements about flames some of them are true while others are
hoa [83]

Answer:

i)The carbon particles are formed when the gas is not completely burnt(True)

ii)A solid or liquid must be change to gaseous state in order to make flame(TRUE)

iii)A non- luminous Bunsen flame produces has three visible regions(FALSE)

iv)The luminous Bunsen flame produces less soot than the non- luminous flame(FALSE)

v)A yellow Bunsen flame is obtained when the air holes are opened(FALSE)

vi)The luminous Bunsen flame is hotter than a non- luminous Bunsen flame(FALSE)

vii)Bunsen burner uses kerosene as a source of heat(FALSE)

Explanation:

i)When the incomplete combustion ,then CO(carbon monoxide) and C(carbon) are produced. <u>The unburnt carbon get deposited as</u><u> Soot</u>.

In complete combustion CO2(carbon dioxide) is produced.

ii)Fire, is the mixture of hot gases.Flame are result of chemical reaction between oxygen and fuel(e.g butane ,wood).Flame contain,carbon dioxide , heat ,light,steam.

iii)There are total three regions of flame in which the outer most region is the non-luminous .The non-luminous part is <u>blue(one visible region</u>) and does not emit-light.

iv) Luminous Bunsen flame produces more soot than the non- luminous flame because luminous flame contain more unburnt particles as compare to non-luminous.

luminous part has less oxygen available for complete combustion of fuel

v)When the air hole is open it means excess oxygen is supplied to the fuel.

In this case clean and luminous flame is produced.When air hole is close yellow flame is produced.

vi)Non-luminous part of flame is more hot because of complete combustion due to proper availability  of oxygen. Sometime the particle of non-luminous flame get ionize also.

vii).The bunsen burner uses Natural gas(methane) or LPG(propane and butane)as sources of heat because these are easily burnt not kerosene.

4 0
3 years ago
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