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xxMikexx [17]
3 years ago
11

Predict whether the bond between each pair of atoms will be no polar convalent, polar covalent or ionic

Chemistry
1 answer:
bekas [8.4K]3 years ago
7 0
Yes sir I’m not sure why what I said so yes sir I’m not gonna go to the bathroom I’m just gonna go home I’m gonna be there in about a week or two I don’t uueiueyey
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g Calculate the pH when (a) 24.9 mL and (b) 25.1 mL of 0.100 M HNO3 have been added to 25.0 mL of 0.100 M KOH solution.
jarptica [38.1K]

Answer:

Following are the responses to the given choices:

Explanation:

For point a:

Using the acid and base which are strong so,

moles of H^+ (fromHNO_3)

= 24.9\ mL \times 0.100\ M \\\\= \frac{24.9}{1000\ L} \times 0.100\  M \\\\= 2.49 \times 10^{-3} \ mol

moles of OH^{-} (from KOH)

= 25.0\ mL \times 0.100\ M \\\\= \frac{25.0}{1000 \ L} \times 0.100 \ M \\\\\= 2.50 \times  10^{-3}\  mol  

1\ mol H^{+} \ neutralizes\  1\ mol\  of\  OH^{-}

So,  (2.50 \times 10^{-3} mol - 2.49 \times 10^{-3} mol) i.e. 1 \times 10^{-5} mol of OH^- in excess in total volume (24.9+25.0) \ mL = 49.9 \ mL i.e. concentration of OH^- = 2 \times 10^{-4}\ M

p[OH^{-}] = -\log [OH^{-}] = -\log [2 \times 10^{-4}\ mol] = 3.70

Since, pH + pOH = 14,

so,

\to pH = 14- pOH = 14- 3.70 = 10.30  

For point b:

moles of OH^- = from point a = 2.50 \times 10^{-3} \ mol

moles of H^+(fromHNO_3):

= 25.1 mL \times 0.100 M\\\\ = \frac{25.1}{1000}\ L \times 0.100 \ M\\\\ = 2.51\times 10^{-3} \ mol

1 mol H^+ neutralizes 1 mol of OH^-

So, (2.51 \times 10^{-3}\ mol - 2.50 \times 10^{-3}\ mol) i.e. 1 \times 10^{-5} \ mol \ of\  H^+ in excess in the total volume of (25.1+25.0) \ mL = 50.1\ mL i.e. concentration ofH^+ = 2 \times 10^{-4}\  M

Hence, pH = -\log [H^+] = -\log[2 \times 10^{-4}] = 3.70

6 0
3 years ago
Через 100 мл одномолярного раствора гидроксида натрия пропустили 896 мл (н.у.) углекислого
fgiga [73]
Yes it is right sir or ma’am
6 0
3 years ago
Balance the following skeleton reaction and identify the oxidizing and reducing agents: Include the states of all reactants and
coldgirl [10]

Answer :

a. The oxidizing agent is: BH_4^-

b. The reducing agent is: ClO_3^-

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

Reducing agent : It is defined as the agent which helps the other substance to reduce and itself gets oxidized. Thus, it will undergo oxidation reaction.

Oxidizing agent : It is defined as the agent which helps the other substance to oxidize and itself gets reduced. Thus, it will undergo reduction reaction.

The given chemical reaction is,

BH_4^-(aq)+ClO_3^-(aq)\rightarrow H_2BO_3^-(aq)+Cl^-(aq)

The oxidation-reduction half reaction will be :

Oxidation : BH_4^-\rightarrow H_2BO_3^-

Reduction : ClO_3^-\rightarrow Cl^-

Now balance oxygen atom on both side.

Oxidation : BH_4^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-  

Now balance hydrogen atom on both side.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O

Reduction : ClO_3^-+3H_2O\rightarrow Cl^-+6OH^-

Now balance the charge.

Oxidation : BH_4^-+4OH^-\rightarrow H_2BO_3^-+3H_2O+4e^-

Reduction : ClO_3^-+3H_2O+6e^-\rightarrow Cl^-+6OH^-

In order to balance the electrons, we multiply the oxidation reaction by 6 and reduction reaction by 4 and then added both equation, we get the balanced redox reaction.

Oxidation : 6BH_4^-+24OH^-\rightarrow 6H_2BO_3^-+18H_2O+24e^-

Reduction : 4ClO_3^-+12H_2O+24e^-\rightarrow 4Cl^-+24OH^-

The balanced chemical equation in acidic medium will be,

6BH_4^-+4ClO_3^-\rightarrow 6H_2BO_3^-+6H_2O+4Cl^-

3BH_4^-+2ClO_3^-\rightarrow 3H_2BO_3^-+3H_2O+2Cl^-

In the redox reaction, ClO_3^- act as oxidizing agent and BH_4^- act as an reducing agent.

7 0
3 years ago
A 35 gram of saturated solution is distilled out completely. If the solubility of the solute is 110, find the amount of residue
kipiarov [429]

Answer:

3850g

Explanation:

Solubility is the amount of solute dissolved in a solvent.

Solubility is mass of solute÷mass of solvent

The solvent is 35grams

Solute?

Solubility of solute is 110

110=x/35

= 110 × 35

The amount of residue solute is 3850g

8 0
3 years ago
There are 64 pretzels in a 16-ounce bag how many proportion would be in a 5-ounce bag?
qwelly [4]

Answer:

20 pretzels.

Explanation:

So in the first bag there at 64 pretzels in 16-ounces.

We can divide both these numbers by 16, to get 4 pretzels per ounce.

If we multiply both numbers by 5, we get 20 pretzels per ounces.

So, 20 pretzels i5-ounce bag.

3 0
3 years ago
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