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2 years ago

1.Calculate the mass of compound required to prepare 100.00 mL of a 1.40x10-2M CuCl2.Show your work.

Chemistry

1 answer:

Verdich [7]2 years ago

5 0

The concentration of the diluted solution is 0.0625 M.

<h3>What is concentration?</h3>

The term concentration refers to the amount of substance present in solution.

1) To find the mass of the compound;

mass/134 g/mol = 1.40x10-2M × 100/1000

mass = 1.40x10-2M × 100/1000 × 134 g/mol

mass = 0.19 g

2) To find the molarity of the solution;

2.50 g/40 = 100/1000 × M

M = 2.50 g/40 × 1000/100

M = 0.625 M

3) Using;

C1V1 = C2V2

0.625 M × 10.00mL = C2 × 100.00 mL

C2 = 0.625 M × 10.00mL/ 100.00 mL

C2 = 0.0625 M

Learn more about concentration: brainly.com/question/3045247

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Please Help, will give 30 points! The following data was collected when a reaction was performed experimentally in the laborator

Sedaia [141]

Answer:

9 moles of NaNO3.

Explanation:

The balanced equation for the reaction is given below:

Al(NO3)3 + 3NaCl —> 3NaNO3 + AlCl3

Next, we shall determine the number of mole of Al(NO3)3 and NaCl that reacted and the number of mole of NaNO3 produced from the balanced equation.

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl to produce 3 moles of NaNO3.

Next, we shall determine the limiting reactant.

The limiting reactant can be obtained as follow:

From the balanced equation above,

1 mole of Al(NO3)3 reacted with 3 moles of NaCl.

Therefore, 4 moles of Al(NO3)3 will react with = (4 x 3)/1 = 12 moles of NaCl.

From the calculations made above, we can see that it will take a higher amount i.e 12 moles than what was given i.e 9 moles of NaCl to react completely with 4 moles of Al(NO3)3.

Therefore, NaCl is the limiting reactant and Al(NO3)3 is the excess reactant.

Finally, we shall determine the maximum amount of NaNO3 produced from the reaction.

In this case, the limiting reactant will be used as it will produce the maximum amount of NaNO3 since all of it is consumed by the reaction.

The limit reactant is NaCl and the maximum amount of NaNO3 produced can be obtained as follow:

From the balanced equation above,

3 moles of NaCl reacted to produce 3 moles of NaNO3.

Therefore, 9 moles of NaCl will also react to produce 9 moles of NaNO3.

From the calculations made above, the maximum amount of NaNO3 produced is 9 moles

6 0

3 years ago

PLEASE ANSWER NEED BY MIDNIGHT TONIGHT!!!!!!

maksim [4K]

The equation for carbon-14 emission by Radium-223 nuclei is given below:

$^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C$

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of a substance with emission of radiation.

The equation for carbon-14 emission by Radium-223 nuclei is given below:

$^{223}_{88}Ra \rightarrow\: ^{209}_{82}Pb + \:^{14}_{6}C$

In conclusion, the emission of carbon-14 by Radium-223 nuclei produces Lead-209 nuclei.

Learn more about radioactivity at: brainly.com/question/3603596

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5 0

1 year ago

Help me now plssssssss i will give brainliest!!!!!!!!!!!!!!!!!!!!!!!

Blababa [14]

Products are copper+ aluminium chloride
reactants are aluminium+copper chloride

5 0

3 years ago

Consider the following system at equilibrium where H° = 111 kJ/mol, and Kc = 6.30, at 723 K.

Rashid [163]

Answer:

1) The value of Kc:

C. remains the same.

2) The value of Qc:

A. is greater than Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium.

4) The concentration of N2 will:

B. decrease.

Explanation:

Hello,

In this case, by means of the Le Chatelier's principle which is based on the shift a chemical reaction could have under some modifications, we have:

1) The value of Kc:

C. remains the same, since it just depend the reaction's thermodynamics as it is computed via:

$ln(K)=\frac{\Delta _RG}{RT}$

2) The value of Qc:

A. is greater than Kc, since the reaction quotient is:

$Qc=\frac{[N_2][H_2]^3}{[NH_3]^2}$

Thus, the lower the concentration of ammonia, the higher Qc, making Qc>Kc.

3) The reaction must:

B. run in the reverse direction to restablish equilibrium, since ammonia was withdrawn and should be regenerated to reach the equilibrium.

4) The concentration of N2 will:

B. decrease, since less reactant is forming the products.

Best regards.

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4 years ago

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The most simple level of organization in living things is the tissue level.

murzikaleks [220]

<span>The simplest level of organization for living things is a single organelle, which is composed of aggregates of macromolecules. so it is false</span>

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3 years ago

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