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bixtya [17]
3 years ago
9

What’s the volume of the cake if the radius is 8 inches and the height is 5 inches?

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

1005 in^3

Step-by-step explanation:

Think of this cake as a cylindrical solid of base radius 8 in and height 5 in.

The volume is V = (base area)(height), which here is:

                        V = (pi)*(8 in)^2*(5 in) = 320pi in^3, or approximately 1005 in^3

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Estimate 76.216+66.36 by first rounding each number to the nearest whole number.
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Answer:

142

Step-by-step explanation:

  • Round the numbers to their nearest WHOLE NUMBER.

76.216=76\\66.36=66

  • Then ADD

76+66=142

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A Web music store offers two versions of a popular song. The size of the standard version is 2.4 megabytes (MB). The size of the
Margarita [4]

Answer:

880 high-quality version

Step-by-step explanation:

I think the below is your full question:

<em>A Web music store offers two versions of a popular song. The size of the standard version is 2.1megabytes (MB). The size of the high-quality version is 4.5 MB. Yesterday, there were 1290 downloads of the song, for a total download size of 4821 MB. How many downloads of the high-quality version were there?</em>

Here is my answer:

Let x is the number of high-quality version

So the number of standard version= 1290 - x

We also know:  total download size of 4821 MB. which means:

4.5x + 2.1(1290-x) = 4821

<=> 4.5x+2709-2.1x=4821

<=> 2.4x=2112

<=> x=880

So there were 880 high-quality version

5 0
3 years ago
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Nu is designing a rectangular sandbox.The bottomm is 16 square feet.Which dimensions require the least amount of materail for th
zzz [600]

Given Information:  

Area of rectangle = 16 square feet

Required Information:  

Least amount of material = ?

Answer:

x = 4 ft and y = 4 ft

Step-by-step explanation:

We know that a rectangle has area = xy and perimeter = 2x + 2y

We want to use least amount of material to design the sandbox which means we want to minimize the perimeter which can be done by taking the derivative of perimeter and then setting it equal to 0.

So we have

xy = 16  

y = 16/x

p = 2x + 2y

put the value of y into the equation of perimeter

p = 2x + 2(16/x)

p = 2x + 32/x

Take derivative with respect to x

d/dt (2x + 32/x)

2 - 32/x²

set the derivative equal to zero to minimize the perimeter

2 - 32/x² = 0

32/x² = 2

x² = 32/2

x² = 16

x = \sqrt{16} = 4 ft

put the value of x into equation xy = 16

(4)y = 16

y = 16/4

y = 4 ft

So the dimensions are x = 4 ft and y = 4 ft in order to use least amount of material.

Verification:

xy = 16

4*4 = 16

16 = 16 (satisfied)

7 0
3 years ago
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