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3 years ago

LITRALLY HELP PLS

2 answers:

7 0

The formula to find the surface area depends on the shape. However, you can find the area of each face of the shape, then add them all together. This concept of surface area can be used in the real world, and is everyday. When drawing blueprints or building a house, architects need to calculate surface area.

Angelina_Jolie [31]3 years ago

4 0

Answer:

Halo!!! i wrote my answer below your epic btw

Step-by-step explanation:

you first have to break up the surface of the shape into smaller shapes so that they are easier to work with. you then calculate all of the shapes and add them together. this can be used in the real world to find the area of houses when you need to find how much space an area of the house has.

PS:If u didnt learn to find surface area this way insert anything you want into the beggining sorry i dont know what youve been learning

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Find sum or difference. -1/2 + 1/3

Free_Kalibri [48]

2/5 is the answer unless your multiplying

6 0

3 years ago

viktelen [127]

Answer:

A. y = 2^x + 5

Step-by-step explanation:

The equation is not linear, so a constant slope does not exist.

Not Linear PARALLEL

...................................................................................................................................................

The equation is not linear, so a constant slope does not exist.

Not Linear PERPENDICULAR

...............................................................................................................................................

First, remember that if two lines are parallel, they have the same slope. The problem already gave us a point on the line and we now have the power to find the slope. Since we have the slope and a point on the line, we are going to find the equation of the line through the point-slope formula, which is:

is a point on the line

is the slope of the line

The equation given to us has a slope of 2, as we can see because the line is in slope-intercept form. Also, we are given the point (3, 11), which we are told is on the line. Since we are already given all of the information for the point-slope formula, we can simply substitute it in and solve for the equation.

Set up

Use the Distributive Property on both sides

Add 11 to both sides and simplify

The equation of our line is y = 2x + 5.

...............................................................................................................................................

Slope-intercept form:

y = mx + b "m" is the slope, "b" is the y-intercept (the y value when x = 0)

For lines to be parallel, they have to have the SAME slope.

The given line's slope is 2, so the parallel line's slope is also 2.

y = 2x + b

To find "b", plug in the point (3,11) into the equation.

y = 2x + b

11 = 2(3) + b Multiply 2 and 3

11 = 6 + b Subtract 6 on both sides

5 = b

y = 2x + 5

3 0

3 years ago

Solve 5/4=y-1/4 y= p

zmey [24]

The answer can be either y = 1.5 or y = 1 1/2

3 0

3 years ago

A box with a hinged lid is to be made out of a rectangular piece of cardboard that measures 3 centimeters by 5 centimeters. Six

Zarrin [17]

Answer:

The volume of the box is maximized when x = 0.53 cm

Therefore, x = 0.53 cm and the Maximum volume = 1.75 cm³

Step-by-step explanation:

Please refer to the attached diagram:

The volume of the box is given by

$V = Length \times Width \times Height \\\\$

Let x denotes the length of the sides of the square as shown in the diagram.

The width of shaded region is given by

$Width = 3 - 2x \\\\$

The length of shaded region is given by

$Length = \frac{1}{2} (5 - 3x) \\\\$

So, the volume of the box becomes,

$V = \frac{1}{2} (5 - 3x) \times (3 - 2x) \times x \\\\V = \frac{1}{2} (5 - 3x) \times (3x - 2x^2) \\\\V = \frac{1}{2} (15x -10x^2 -9 x^2 + 6 x^3) \\\\V = \frac{1}{2} (6x^3 -19x^2 + 15x) \\\\$

Take the derivative of volume and set it to zero.

$\frac{dV}{dx} = 0 \\\\\frac{dV}{dx} = \frac{d}{dx} ( \frac{1}{2} (6x^3 -19x^2 + 15x)) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\\frac{dV}{dx} = \frac{1}{2} (18x^2 -38x + 15) \\\\0 = \frac{1}{2} (18x^2 -38x + 15)\\\\18x^2 -38x + 15 = 0\\\\$

We may solve the quadratic equation using the quadratic formula.

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

The values of coefficients a, b, c are

$a = 18 \\\\b = -38 \\\\c = 15 \\\\$

Substituting the values into quadratic formula yields,

$x=\frac{-(-38)\pm\sqrt{(-38)^2-4(18)(15)}}{2(18)} \\\\x=\frac{38\pm\sqrt{(1444- 1080}}{36} \\\\x=\frac{38\pm\sqrt{(364}}{36} \\\\x=\frac{38\pm 19.078}{36} \\\\x=\frac{38 + 19.078}{36} \: or \: x=\frac{38 - 19.078}{36}\\\\x= 1.59 \: or \: x = 0.53 \\\\$