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kozerog [31]
3 years ago
9

Giving 5 stars to right one

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0
1/2(20)(15)+3.14(20)(20)+28(40)
=150+1256+68
=1474 sqft
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What is the distance between -2.2 , 8.4 on a number line
leonid [27]

Answer:

10.2

Step-by-step explanation:

if u write is down with the decimals tgat and count that is what u would get also 2 plus 8 is ten and two pluse two is 41

5 0
2 years ago
For each ordered pair determine whether it’s a solution to <br> Y=6x-4
prisoha [69]

Answer:

The answer is in the image

Step-by-step explanation:

8 0
2 years ago
A hemispherical tank is filled with water and has a diameter of 19 feet. If water
pogonyaev

We know that the volume of a sphere is:

V

=

4

3

π

r

3

where

r

=

10

2

=

5

ft

is the radius;

we need half of this, so we use:

V

2

=

2

3

π

r

3

=

261.8

ft

3

giving a total weight of water of:

W

=

261.8

⋅

62.4

=

16

,

336

pounds

6 0
3 years ago
Read 2 more answers
What is the solution for <br> 8x+2y=13<br> 4x+y=11<br> In substitution method
padilas [110]
Solve for y in 4x+y=11

4x + y = 11
<span>y = 11 − 4x

</span>Substitute <span>y = 11 - 4x</span> into <span>8x + 2y =13 

22 = 13

</span>Since <span>22 = 13</span><span> is not true, this is an inconsistent system.
</span>
So, no solution. 

Hope this helped! :D
3 0
4 years ago
What is the exact area and arc length of these sectors? Please helppp
Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = \frac{90}{360} \times \pi \times 12^2 = 36\pi

2. Area of sector 2 = \frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi

3. Area of sector 3 = \frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi

4. Area of sector 4 = \frac{270}{360} \times \pi \times 6^2 = 27 \pi

5. Arc length of sector 1 = \frac{90}{360} \times 2 \times \pi \times 12 = 6\pi

6. Arc length of sector 2 = \frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi

7. Arc length of sector 3 = \frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi

8. Arc length of sector 4 = \frac{270}{360} \times 2 \times \pi \times 6 = 9\pi

4 0
3 years ago
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