Since none of the terms have the same variables the like terms would be (A) because they are both constants
3x+7=-x-1
move -x to the other side
sign changes from -x to +x
3x+x+7=-x+x-1
3x+x+7=-1
4x+7=-1
move 7 to the other side
sign changes from +7 to -7
4x+7-7=-1-7
4x=-8
Divide by 4 for both sides
4x/4=-8/4
Answer: x=-2
Answer:
x+3y-6=0
Step-by-step explanation:
given eqn is y=3x-2 which is 3x-y-2=0
the eqn of line perpendicular to given eqn is -x+3y+k=0
it passes through (6,4)
-6+3*4+k=0
or,. -6+12+k=0
or, k= -6
therefore, the eqn of line perpendicular to given eqn is x+3y-6=0
Step-by-step explanation:
f(x) = 2x² + 9
f(5) = 2(5)² + 9
= 2(25) + 9
= 50 + 9
= 59
