All categories

3 years ago

X > -2 Open or closed dot

Mathematics

1 answer:

Ann [662]3 years ago

8 0

Answer:

What do u mean more info pls

Step-by-step explanation:

You might be interested in

Help me! please will name brainliest

enot [183]

Answer:

It will be a mixed fraction so it will be 3 \frac{248}{999}

Step-by-step explanation:

$3 \frac{248}{999}$

6 0

3 years ago

The locations in a city are mapped out on a grid, where the origin represents the city center. A traffic helicopter travels due

Elenna [48]

Answer:

Helicopter have traveled 5.55 units of distance approximately if it went directly from one location to the other.

Step-by-step explanation:

We are given the following in the question:

A traffic helicopter travels due north and then due east to get to the location at (-3,4) to the location at (7,13).

The attached image shows the path of helicopter.

Distance Formula:

$(x_1,y_1), (x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

Distance traveled by helicopter =

$d((-3,4),(-3,13)) + d((-3,13),(7,13))\\\\=\sqrt{(-3+3)^2 + (13-4)^2} + \sqrt{(7+3)^2 + (13-13)^2}\\= 9+10\\= 19 \text{ units}$

If the helicopter goes directly:

$d((-3,4),(7,13))\\\\=\sqrt{(7+3)^2+(13-4)^2}\\\approx 13.45 \text{ units}$

Difference in distances =

$19 - 13.45 = 5.55\text{ units}$

Thus, helicopter have traveled 5.55 units of distance approximately if it went directly from one location to the other.

7 0

4 years ago

Use the law of sines to find the length of side c (answer as soon as possible)

Serggg [28]

Answer:

Step-by-step explanation:

Using the law of sines in ΔABC, then

$\frac{c}{sinC}$ = $\frac{a}{sinA}$

Substituting in values gives

$\frac{c}{sin31.6}$ = $\frac{25}{sin38}$ ( cross- multiply )

c × sin38° = 25 × sin31.6° ( divide both sides by sin38° )

c = $\frac{25(sin31.6)}{sin38}$ ≈ 21.28 → D

7 0

4 years ago

Luke hiked 6 1/4 miles . Joana hiked 2 1/5 times as far .How far did Joana hiked

vazorg [7]

Answer:

$6 \frac{1}{4} =\frac{25}{4} \\\\2 \frac{1}{5} = \frac{11}{2}\\\\$

$\frac{25}{4} \times \frac{11}{2} = \frac{275}{8}=34 \frac{3}{8}$ (Amount Jona hiked)

3 0

4 years ago

Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)

DaniilM [7]

$5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x$

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

$10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0$

Now the zero product property tells us that there are two cases where this is true,

$\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}$

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of $\dfrac\pi2$ , so $x=\dfrac{(2n+1)\pi}2$ where $n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}$

which occurs twice in the interval $[0,2\pi)$ for $x=\arcsin\dfrac3{10}$ and $x=\pi-\arcsin\dfrac3{10}$ . More generally, if you think of $x$ as a point on the unit circle, this occurs whenever $x$ also completes a full revolution about the origin. This means for any integer $n$ , the general solution in this case would be $x=\arcsin\dfrac3{10}+2n\pi$ and $x=\pi-\arcsin\dfrac3{10}+2n\pi$ .

6 0

3 years ago