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lora16 [44]
3 years ago
11

X > -2 Open or closed dot

Mathematics
1 answer:
Ann [662]3 years ago
8 0

Answer:

What do u mean more info pls

Step-by-step explanation:

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Help me! please will name brainliest
enot [183]

Answer:

It will be a mixed fraction so it will be 3 \frac{248}{999}

Step-by-step explanation:

3 \frac{248}{999}

6 0
3 years ago
The locations in a city are mapped out on a grid, where the origin represents the city center. A traffic helicopter travels due
Elenna [48]

Answer:

Helicopter have traveled  5.55 units of distance approximately  if it went directly from one location to the other.

Step-by-step explanation:

We are given the following in the question:

A traffic helicopter travels due north and then due east to get to the location at (-3,4) to the location at (7,13).

The attached image shows the path of helicopter.

Distance Formula:

(x_1,y_1), (x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}

Distance traveled by helicopter =

d((-3,4),(-3,13)) + d((-3,13),(7,13))\\\\=\sqrt{(-3+3)^2 + (13-4)^2} + \sqrt{(7+3)^2 + (13-13)^2}\\= 9+10\\= 19 \text{ units}

If the helicopter goes directly:

d((-3,4),(7,13))\\\\=\sqrt{(7+3)^2+(13-4)^2}\\\approx 13.45 \text{ units}

Difference in distances =

19 - 13.45 = 5.55\text{ units}

Thus, helicopter have traveled  5.55 units of distance approximately  if it went directly from one location to the other.

7 0
4 years ago
Use the law of sines to find the length of side c (answer as soon as possible)
Serggg [28]

Answer:

D

Step-by-step explanation:

Using the law of sines in ΔABC, then

\frac{c}{sinC} = \frac{a}{sinA}

Substituting in values gives

\frac{c}{sin31.6} = \frac{25}{sin38} ( cross- multiply )

c × sin38° = 25 × sin31.6° ( divide both sides by sin38° )

c = \frac{25(sin31.6)}{sin38} ≈ 21.28 → D

7 0
4 years ago
Luke hiked 6 1/4 miles . Joana hiked 2 1/5 times as far .How far did Joana hiked​
vazorg [7]

Answer:

6 \frac{1}{4} =\frac{25}{4} \\\\2 \frac{1}{5} = \frac{11}{2}\\\\

\frac{25}{4} \times \frac{11}{2} = \frac{275}{8}=34 \frac{3}{8} (Amount Jona hiked)

3 0
4 years ago
Solve using algebraic equation: <br> 5sin2x=3cosx<br><br> (No exponents)
DaniilM [7]
5\sin2x=3\cos x\iff10\sin x\cos x=3\cos x

by the double angle identity for sine. Move everything to one side and factor out the cosine term.

10\sin x\cos x=3\cos x\iff10\sin x\cos x-3\cos x=\cos x(10\sin x-3)=0

Now the zero product property tells us that there are two cases where this is true,

\begin{cases}\cos x=0\\10\sin x-3=0\end{cases}

In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of \dfrac\pi2, so x=\dfrac{(2n+1)\pi}2 where n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}

which occurs twice in the interval [0,2\pi) for x=\arcsin\dfrac3{10} and x=\pi-\arcsin\dfrac3{10}. More generally, if you think of x as a point on the unit circle, this occurs whenever x also completes a full revolution about the origin. This means for any integer n, the general solution in this case would be x=\arcsin\dfrac3{10}+2n\pi and x=\pi-\arcsin\dfrac3{10}+2n\pi.
6 0
3 years ago
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