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3 years ago

Describe the Transformations that takes f(x) = x+1 to g(x) = -x+4

1 answer:

5 0

The sign on the 'x' changes, this implies a reflection.

g(x) = -f(x) = -(x+1) = -x -1

Now apply a vertical translation 'up 5' to f(x)

g(x) = -f(x) + 5 = (-x-1) +5 = -x +4

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a farmer is putting up a rectangular pasture. it measures 320 feet by 335 feet it costs $8 per foot, how much will it cost

Anvisha [2.4K]

Answer:

I think it would cost $13,400

Step-by-step explanation:

if you do 320 times 335 you get 107200 and then if you divide that by 107,200 you get $13,400

8 0

3 years ago

(-∞-)help me help me help me help me help me help me help me help me help me help me help me help me help me help me help me hel

ella [17]

Answer:

Zero

Step-by-step explanation:

So we start out on a positive 7. We then add a negative (You just subtract) 7. Modified equation: 7-7

7 minus 7 equals 0 or {7 - 7 = 0}

Hope this helps!!

3 0

3 years ago

Read 2 more answers

Suppose that X has a Poisson distribution with a mean of 64. Approximate the following probabilities. Round the answers to 4 dec

o-na [289]

Answer:

(a) The probability of the event (X > 84) is 0.007.

(b) The probability of the event (X < 64) is 0.483.

Step-by-step explanation:

The random variable X follows a Poisson distribution with parameter λ = 64.

The probability mass function of a Poisson distribution is:

$P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0, 1, 2, ...$

(a)

Compute the probability of the event (X > 84) as follows:

P (X > 84) = 1 - P (X ≤ 84)

$=1-\sum _{x=0}^{x=84}\frac{e^{-64}(64)^{x}}{x!}\\=1-[e^{-64}\sum _{x=0}^{x=84}\frac{(64)^{x}}{x!}]\\=1-[e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{84}}{84!}]]\\=1-0.99308\\=0.00692\\\approx0.007$

Thus, the probability of the event (X > 84) is 0.007.

(b)

Compute the probability of the event (X < 64) as follows:

P (X < 64) = P (X = 0) + P (X = 1) + P (X = 2) + ... + P (X = 63)

$=\sum _{x=0}^{x=63}\frac{e^{-64}(64)^{x}}{x!}\\=e^{-64}\sum _{x=0}^{x=63}\frac{(64)^{x}}{x!}\\=e^{-64}[\frac{(64)^{0}}{0!}+\frac{(64)^{1}}{1!}+\frac{(64)^{2}}{2!}+...+\frac{(64)^{63}}{63!}]\\=0.48338\\\approx0.483$

Thus, the probability of the event (X < 64) is 0.483.

5 0

3 years ago

April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R

Ymorist [56]

The complement of "April choosing five Pop CDs" is "Choosing five CDs where not all of them are Pop", making the second option a right choice.

In the question, we are given that April is randomly choosing five CDs to bring in her car from the following: 6 Pop CDs, 8 Rock CDs, and 10 R&B CDs.

We are asked what will be the complement of April choosing 5 Pop CDs.

The complement of a set is the one, where no element of the original set is present.

The original set is that "April is choosing 5 Pop CDs".

This means that April, while choosing 5 CDs from the given set, chooses all 5 CDs to be Pop.

While making the complement we need to change the final outcome.

To change this, we just need to make one exception to this, which can be achieved by making one other than Pop CD.

This gives us the set: "Choosing 5 CDs where not all of them are complement".

Thus, the complement of "April choosing five Pop CDs" is "Choosing five CDs where not all of them are Pop", making the second option a right choice.

Learn more about the complement of an event at

brainly.com/question/3728788

#SPJ4

The given question is incomplete. The complete question is:

"April is randomly choosing five CDs to bring in her car from the following: 6 pop CDs, 8 rock CDs, and 10 R&B CDs. What is the complement of April choosing five pop CDs?

choosing five CDs where none of them are pop

choosing five CDs where not all of them are pop

choosing five CDs where at least one of them is pop

choosing five CDs where all of them are pop"

7 0

2 years ago

Natasha is 5 years older than Alex. Fiona is 10 years younger

Sergio039 [100]

The answer fam is..........

Alex is 20

Fiona is 10

Natasha is 25

5 0

3 years ago