(f o g) = 2(3x - 6)^2 + 3(3x - 6) - 10
(f o g) = 2(9x^2 - 36x + 36) + 9x - 18 - 10
(f o g) = 18x^2 - 72x + 72 + 9x - 28
(f o g) = 18x^2 - 63x + 44
(f o g)(3) = 18(3)^2 - 63(3) + 44
= 162 - 189 + 44
= -27 + 44
= 17
Answer:
See explanation
Step-by-step explanation:
<u>Given:</u> ΔABC ≅ ΔDEF
AM, DN - medians
<u>Prove:</u> AM ≅ DN
Proof:
1. Congruent triangles ABC and DEF have congruent corresponding parts:
- AB ≅ DE;
- BC ≅ EF;
- ∠ABC ≅ ∠DEF.
2. BM ≅ MC - definition of the median AM;
3. EN ≅ NF - definition of the median DN;
4. AB ≅ 2BM, EF ≅ 2EN
BM ≅ 1/2 AB,
EN ≅ 1/2 EF,
thus, BM ≅ EN
5. Consider two triangles ABM and DEN. In these triangles \:
- AB ≅ DE (see 1));
- BM ≅ EN (see 4));
- ∠ABM ≅ ∠DEN (see 1).
So, ΔABM ≅ ΔDEN by SAS postulate.
6. Congruent triangles ABM and DEN have congruent corresponding sides BM and DN.
Answer:
3 + 7x = 7x + 3
Step-by-step explanation:
Simplifying
7x + 3 = 7x + 3
48 ÷ 24 = 2
24 goes into 48 2 times.