Step-by-step explanation:
z
3
=8(cos216
∘
+isin216
∘
)
z^3=2^3(\cos(6^3)^\circ+i\sin(6^3)^\circ)z
3
=2
3
(cos(6
3
)
∘
+isin(6
3
)
∘
)
\implies z=8^{1/3}\left(\cos\left(\dfrac{216+360k}3\right)^\circ+i\sin\left(\dfrac{216+360k}3\right)^\circ\right)⟹z=8
1/3
(cos(
3
216+360k
)
∘
+isin(
3
216+360k
)
∘
)
where k=0,1,2k=0,1,2 . So the third roots are
\begin{gathered}z=\begin{cases}2(\cos72^\circ+i\sin72^\circ)\\2(\cos192^\circ+i\sin192^\circ)\\2(\cos312^\circ+i\sin312^\circ)\end{cases}\end{gathered}
z=
⎩
⎪
⎪
⎨
⎪
⎪
⎧
2(cos72
∘
+isin72
∘
)
2(cos192
∘
+isin192
∘
)
2(cos312
∘
+isin312
∘
)
Hey there,
I would think that the value of x would be in the range of 40-45 because the x side is alot bigger than the other sides.
~Jurgen
Answer:
23
Step-by-step explanation:
133 = 18 + 5x
155 = 5x
23 = x
Answer:
D and E, or 56 and 60
Step-by-step explanation:
The inequality says the value must be greater than or equal to 50, so that can take out the first two (0 and 50), since they do not fit this criteria. 50.5 also does not work, because the club cannot sell half a candle. Therefor, the last two choices are the only ones that make sense in the context of the situation.
