Answer:
a. 

c. No. Delicious Candy isn't violating any government regulations
Step-by-step explanation:
a.
-A uniform distribution is given by the formula:

#we substitute our values in the formula above to determine the distribution:

Hence, the probability density function for the box's weight is given as: 
b. The probability of the box's weight being exactly 32 ounces is obtained by integrating f(x) over a=b=32:
![f(x)=1.25, \ \ \ a\leq x\leq b\\\\=\int\limits^{32}_{32} {1.25} \, dx \\\\\\=[1.25x]\limits^{32}_{32}\\\\\\=1.25[32.0-32.0]\\\\\\=0](https://tex.z-dn.net/?f=f%28x%29%3D1.25%2C%20%5C%20%5C%20%5C%20a%5Cleq%20x%5Cleq%20b%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B32%7D_%7B32%7D%20%7B1.25%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%5C%5C%3D%5B1.25x%5D%5Climits%5E%7B32%7D_%7B32%7D%5C%5C%5C%5C%5C%5C%3D1.25%5B32.0-32.0%5D%5C%5C%5C%5C%5C%5C%3D0)
Hence, the probability that a box weighs exactly 32 ounces is 0.000
ii.The probability that a box weighs more than 32.3 is obtained by integrating f(x) over the limits 32.3 to 32.6 :
![f(x)=1.25, \ \ \ a\leq x\leq b\\\\=\int\limits^{32.6}_{32.3} {1.25} \, dx \\\\\\=[1.25x]\limits^{32.6}_{32.3}\\\\\\=1.25[32.6-32.3]\\\\\\=0.375](https://tex.z-dn.net/?f=f%28x%29%3D1.25%2C%20%5C%20%5C%20%5C%20a%5Cleq%20x%5Cleq%20b%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B32.6%7D_%7B32.3%7D%20%7B1.25%7D%20%5C%2C%20dx%20%5C%5C%5C%5C%5C%5C%3D%5B1.25x%5D%5Climits%5E%7B32.6%7D_%7B32.3%7D%5C%5C%5C%5C%5C%5C%3D1.25%5B32.6-32.3%5D%5C%5C%5C%5C%5C%5C%3D0.375)
Hence, the probability that a box weighs more than 32.3 ounces is 0.3750
iii. The probability that a box weighs less than 31.8 is 0.000 since the weight limits are
.
-Any value above or below these limits have a probability of 0.000
c. Let 32 ounces be the government's stated weight.

Hence, Delicious Candy isn't violating any government's regulations.