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Shtirlitz [24]
3 years ago
13

ANSWER THIS URGENTLY

Mathematics
1 answer:
neonofarm [45]3 years ago
8 0
I think B if not type 1/3 pi 6 squared and add 6.71 or something with the 6.71
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Write the sentence as an equation. Then solve 2 less than one-sixth of a number n is 5
lakkis [162]

Answer:

n=42

Step-by-step explanation:

n/6-2=5

n/6=7

n=42

5 0
3 years ago
-18 = 5v+7 simplify your answer as much as possible what is the solve for v
Pie

Answer:

v = - 5

Step-by-step explanation:

Given

- 18 = 5v + 7 ( subtract 7 from both sides )

- 25 = 5v ( divide both sides by 5 )

- 5 = v

5 0
4 years ago
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Solve for x please help!!!
Harlamova29_29 [7]
X=13 i believe!! hope it helps <3
8 0
3 years ago
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4. A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean
Ede4ka [16]

Adding 2 to each value of the random variable X makes a new random variable X+2. Its mean would be

E[X+2]=E[X]+E[2]=E[X]+2

since expectation is linear, and the expected value of a constant is that constant. E[X] is the mean of X, so the new mean would be

E[X+2]=10+2=12

The variance of a random variable X is

V[X]=E[X^2]-E[X]^2

so the variance of X+2 would be

V[X+2]=E[(X+2)^2]-E[X+2]^2

We already know E[X+2]=12, so simplifying above, we get

V[X+2]=E[X^2+4X+4]-12^2

V[X+2]=E[X^2]+4E[X]+4-12^2

V[X+2]=(V[X]+E[X]^2)+4E[X]-140

Standard deviation is the square root of variance, so V[X]=3^2=9.

\implies V[X+2]=(9+10^2)+4(10)-140=9

so the standard deviation remains unchanged at 3.

NB: More generally, the variance of aX+b for a,b\in\mathbb R is

V[aX+b]=a^2V[X]+b^2V[1]

but the variance of a constant is 0. In this case, a=1, so we're left with V[X+2]=V[X], as expected.

5 0
3 years ago
Please help I’ve been stuck on this for over 20 mins!
fgiga [73]

Answer:

5 1/3

Step-by-step explanation:

2÷3/8=

2*8/3=5 1/3

5 0
3 years ago
Read 2 more answers
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