In a right rectangle, we have:


For your exercice, hypotenuse=12
The exercise also inform the angle 60°, then:

Answer:
6s + 2s - 3s - 6:
5s-6
10t - 4t -6 + 5t:
11t-6
18r + 18r + 9r - 3r:
42r
20 - 4q + 40r - 16:
-4q+40r+4
17st - 16s + t:
17st-16s+t
. 101+101x - x:
101+100x
16a2 - 14a + a2 - 3a:
14 ato the power of 2- 17a
14t + 14t + t:
29t
r + s + rs + s + rs + s:
r+2rs+3s
54 pt - 3p + 4t - 3pt:
51pt-3p+4t
i dont know 11
101c - 5c +4c:
100c
12q - 4 + 10q - 4q +9:
18q+5
21k - 20k + 3k:
4k
181x + 91x - 23x:
249x
Step-by-step explanation:
Answer:
The correct answer would be C
Step-by-step explanation:
Answer:
{8 cm, 15 cm, 17 cm}
Step-by-step explanation:
we know that
The length sides of a right triangle must satisfy the Pythagoras Theorem
so

where
c is the greater side (the hypotenuse)
a and b are the legs (perpendicular sides)
<u><em>Verify each case</em></u>
case 1) we have
{5 cm, 15 cm, 18 cm}
substitute in the formula

----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 2) we have
{6 cm, 12 cm, 16 cm}
substitute in the formula

----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 3) we have
{5 cm, 13 cm, 15 cm}
substitute in the formula

----> is not true
therefore
Sean cannot make a right triangle with this set of lengths
case 4) we have
{8 cm, 15 cm, 17 cm}
substitute in the formula

----> is true
therefore
Sean can make a right triangle with this set of lengths