2 < 3x - 1 < 5 ....add 1 to all sections
2 + 1 < 3x - 1 + 1 < 5 + 1 ...simplify
3 < 3x < 6...now divide all sections by 3
3/3 < (3/3)x < 6/3...simplify
1 < x < 2 <===
but if u have trouble doing it this way, u can split it
2 < 3x - 1 3x - 1 < 5
2 + 1 < 3x 3x < 5 + 1
3 < 3x 3x < 6
3/3 < x x < 6/3
1 < x x < 2
now put them together.....1 < x < 2 <==
either way, u will get the same answer
The division of the polynomial 9x² - 6x - 8 by the polynomial 3x + 2 gives a quotient of 3x - 4 with no remainder
<h3>How to carry out the long division?</h3>
The given parameters are:
- Dividend = 9x² - 6x - 8
- Divisor = 3x + 2
To carry out the division, we continue dividing the leading term of the dividend by the leading term of the divisor
At the end of each division step, the quotient is multiplied by the divisor and the result of the product is subtracted from the dividend.
Using the above step, the result of the division is:
Quotient = 3x - 4
Remainder = 0
See attachment for the steps of the long division
Read more about long division at:
brainly.com/question/12957834
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I believe the answer would be 0 because -0 isn’t really a think so 0 would be the only solution
Answer:I am not your friend but I
Step-by-step explanation:
I have a feeling that the answer 170 in.