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3 years ago

Describe from an administrator perspective what is necessary to prepare a storage device for access by a user.

Computers and Technology

1 answer:

ddd [48]3 years ago

4 0

Answer:

The answer is below

Explanation:

From an administrator perspective, the necessary things to prepare a storage device for access by a user are:

1. Click the Windows key + X key simultaneously and click Device Manager.

2. Widen the Storage Controller.

3. Right-click on the Storage controller Driver and click on Update Driver Software.

4. Wait for some reasonable amount of time before taking the next decision

5. Double check if the issue persists.

6. Restart the PC system to see if the changes have been infected

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Write an application that allows a user to enter the names and birth dates of up to 10 friends. Continue to prompt the user for

mylen [45]

Sorry I don’t know the answer I am really sorry

5 0

4 years ago

if a person walks 10 metres due to south in 10 seconds 10 due east in the next 10 seconds and transmitted you're not in the next

Scorpion4ik [409]

Answer:

$\frac{1}{3}\ m/s$

Explanation:

The computation of the velocity by using the following formula is

As we know that

$Velocity = \frac{Displacement}{Total\ time\ taken}$

where,

Displacement is 10 meters

Total time taken is 30 seconds

Now placing these values to the above formula

So, the velocity of Dash is

$= \frac{10\ meters}{30\ seconds}$

$= \frac{1}{3}\ m/s$

We simply applied the above formula so that we can get the velocity and the same is to be considered

5 0

3 years ago

Which term describes a secure, individual, private cloud-computing model hosted within a public cloud?

grin007 [14]

The term that describes a secure, individual, private cloud-computing model hosted within a public cloud is A hybrid cloud.

<h3>What is this cloud about?</h3>

A hybrid cloud is known to be a system or a model which is said to be a form of a private cloud that is linked with public cloud infrastructure, and it is one that tends to give room for an organization to act workloads in two environments.

Note that In this model, the public cloud is known to be one that is seen and it is one that becomes an extension of the private cloud to make a single, uniform cloud.

Hence, The term that describes a secure, individual, private cloud-computing model hosted within a public cloud is A hybrid cloud.

Learn more about hybrid cloud from

brainly.com/question/27838623

#SPJ1

7 0

1 year ago

Write a program that teaches arithmetic to a young child. The program tests addition and subtraction. In level 1 it tests only a

Natasha2012 [34]

Answer:

import random

class Arithmetics(object):

trial = 2

score = 0

is_end = "Y"

def start(self):

while self. is_end == "Y":

self. level1()

self. level2()

self. level3()

self. is_end = input("Do you want to play again? Y/N: "). upper()

quit()

def level1(self):

print("--------------------Level 1--------------------\n\n Addition:")

for _ in iter(list, 0):

num1 = random.randint(1,5)

num2 = random.randint(1,5)

if self. score == 5:

print("Congrat! advance to next level\n")

self. init_()

break

print(f"{num1} + {num2}")

result = int(input("Your answer: "))

if result == num1 + num2:

self. increase_score()

elif self. trial == 0:

print("Sorry dear, you failed to pass the text.")

self. end_game()

else:

self. trial_reduce()

def level2(self):

print("--------------------Level 2--------------------\n\n Addition again:")

for _ in iter(list, 0):

num1 = random. randint(1,9)

num2 = random. randint(1,9)

if self. score == 5:

print("Congrat! advance to next level\n")

self. init_()

break

print(f"{num1} + {num2}")

result = int(input("Your answer: "))

if result == num1 + num2:

self. increase_score()

elif self. trial == 0:

print("Sorry dear, you failed to pass the text.")

self. end_game()

else:

self. trial_reduce()

def level3(self):

print("--------------------Level 3--------------------\n\n Subtraction:")

for _ in iter(list, 0):

denum = random. randint(6,9)

num = random. randint(1,5)

if self. score == 5:

self. init_()

self. end_game()

break

print(f"{denum} - {num}")

result = int(input("Your answer: "))

if result == denum - num:

self. increase_score()

elif self. trial == 0:

print("Sorry dear, you failed to pass the text.")

self. end_game()

else:

self. trial_reduce()

#classmethod

def trial_reduce(cls):

cls. trial -= 1

#classmethod

def increase_score(cls):

cls. score += 1

#classmethod

def init_(cls):

cls. trial = 2

cls. score = 0

def end_game(self):

print("Congrats kiddo! You are a math wiz.")

game = Arithmetics()

game. start()

Explanation:

The python class defines the arithmetics class with three-level mathematics for children defined as methods for the class. There are three class methods namely; 'trial_reduce', 'increase_score', and 'init_' with each of them decreasing the trial attribute, increasing the score attribute by one, and initializing the class attributes to its initial state.

The 'end_game' prints a message at the end of the program. Each level is in a loop and counts five times if the answers are correct.

7 0

3 years ago

6. Consider a circle of diameter d cm.

blagie [28]

Circles

Area of Circle is $\pi d^{2} /4$

Total percentage increase in the area of the modified circle is 69%

Explanation:

(a) Given the diameter of the circle be d

Then the radius of the circle = r = d/2

and the area of the circle is given by:

Area(A) = $\pi r^{2}$

A = $\pi (d/2)^{2}$

A = $\pi d^{2} /4$

The area of circle is $\pi d^{2} /4$

(b)

The increase in percentage while changing the dimensions is given by the formula :

Total % increase = a% + b% - (a% * b%)/100

Where ,

a% is the percentage increase in side a

b% is the percentage increase in side b

Let the percentage increase in radius is : a%

Since a% = b%

So the formula is

Total increase % = a% + a% + (a% * a%)/100

Given here the diameter of the circle increases by 30% so a =30

Therefore, putting the value of a in the formula

Total increase % = 30% + 30% + (30% *30%)/100

Total increase % = 60% + 9%

Total increase % =69%

Therefore the total percentage increase in the area of the modified circle is 69%

8 0

3 years ago