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DerKrebs [107]
3 years ago
13

The mean temperature for the first 4 days in January was 1°C. 

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
5 0
-4 degrees I think.
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The scale on a map of Indiana is 1 inch=42 miles jill measured the distance on the map from the eastern border to the western bo
Temka [501]

Answer:

Step-by-step explanation:

5 0
4 years ago
Given f(x) shown below complete the equation for the inverse of f(x) = x-1
shtirl [24]
Replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

f(x)=x-1
y=x-1
x=y-1
x+1=y
x+1=f⁻¹(x)
f⁻¹(x)=x+1

3 0
4 years ago
Read 2 more answers
Which type of option helps the importer to hedge risks of exchange rate? A. Put option B. All names are not correct c. Call opti
dalvyx [7]

Answer:

Call option and put option ( D )

Step-by-step explanation:

During hedging in stock/financial markets both the Call and put option can be used to hedge the trading position of the trader against the change in exchange. This is because the call or put option is used depending on the initial position of the trader.

<em>Call option is used when the trader is currently holding a short position</em>

<em>Put option is used when the trader is currently holding a long position</em>

5 0
3 years ago
The managers of 21 supermarkets counted the number of cars in their parking lots on the same day. The results are shown in the l
mixer [17]

The IQR is 42.5

Step-by-step explanation:

Interquartile range is the difference of third and first quartile.

First of all we have to find the median for that purpose the data has to be arranged in ascending order. The data is already in ascending order.

As the number of values are odd

n=21

The median will be: (\frac{n+1}{2}) th\ term

Putting n=21

(\frac{21+1}{2})th\ term\\=(\frac{22}{2})th\ term\\= 11th\ term

The 11th term is 133

So median = 133

Now the data is divided into two halves

One is: 98, 100, 101, 102, 108, 109, 111,118, 129, 132

2nd is: 135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q1 will be the median of first half and Q3 will be the median of 2nd half.

As now the halves contain even number of values, the medians will be the average of middle two values

<u>For First Half:</u>

98, 100, 101, 102, <u>108, 109</u>, 111,118, 129, 132

Q_1 = \frac{108+109}{2}\\Q_1 = \frac{217}{2}\\Q_1 = 108.5

<u>For Second Half:</u>

135, 135, 145, 146, 146, 156, 170 176, 180, 180

Q_2 = \frac{146+156}{2}\\Q_2 = \frac{302}{2}\\Q_2 = 151

Now

<u>Interquartile Range:</u>

IQR = Q_3-Q_1\\= 151-108.5\\=42.5

Hence,

The IQR is 42.5

Keywords: Median, IQR

Learn more about median at:

  • brainly.com/question/10940255
  • brainly.com/question/10941043

#LearnwithBrianly

7 0
3 years ago
150 adults complete a survey.
tresset_1 [31]

Answer:

7:8

Step-by-step explanation:

First, you need to find out how many men there are. 150-80=70 men. The ratio would be 70:80. Then you need to simplify it. the simplified answer is 7:8

8 0
4 years ago
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