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jarptica [38.1K]
2 years ago
9

Which of the following inequalities is represented by the number line?

Mathematics
1 answer:
Rashid [163]2 years ago
6 0
Solid dot with line (arrow) to right so A) x>= 1 is correct
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The tower is 700 meters high. Suppose a building is erected such that the base of the building is on the same plane as the base
adoni [48]

Answer:

10

Step-by-step explanation:

6 0
2 years ago
Does anyone know how to do this question ??
Viktor [21]
Y^2-9^2

(y-9)(y+9)

To see if its right:

y*y+y*9-9*y-9*9
y^2+9y-9y-81
y^2-9^2
4 0
3 years ago
Why does the angle formed by the radius of a circle and a tangent of a circle has a measure of 90 degrees?
drek231 [11]
<span>Theorem:
A tangent to a circle forms a right angle with the circle's radius, at the point of contact of the tangent.</span>
5 0
3 years ago
The polygons are regular polygons. Find the area of the shaded region to the nearest tenth.
Paha777 [63]

Answer:

128.8 cm²

Step-by-step explanation:

In the image attached below, the regular polygon is a square which is composed of a small square and a large square. In a square, all the sides are equal.

For the small square, half of the diagonal is 4 cm, therefore the length of the diagonal is 8 cm (2 × 4 cm). Let the length of the side be a cm, using Pythagoras theorem:

a² + a² = 8²

2a² = 64

a² = 32

a = √32 = 5.7 cm

The area of the small square = length × length = 5.7 × 5.7 = 32.5 cm²

For the large square, half of the diagonal is 9 cm, therefore the length of the diagonal is 18 cm (2 × 9 cm). Let the length of the side be b cm, using Pythagoras theorem:

b² + b² = 18²

2b² = 324

b² = 162

b = √162 = 12.7 cm

The area of the large square = length × length = 12.7 × 12.7 = 161.3 cm²

The area of the shaded region = Area of large square - Area of small square = 161.3 cm² - 32.5 cm² = 128.8 cm²

4 0
3 years ago
Some pleated draperies must be twice as wide as the window they cover. how many square yards of material are needed to cover thi
marusya05 [52]
The window is 2/3 yd by 1 yd, so its area is
.. area = length*width = (2/3 yd)*(1 yd) = 2/3 yd^2

Double that amount of material would be 4/3 yd^2 = 1 1/3 yd^2.
3 0
3 years ago
Read 2 more answers
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