Answer:
- A: 24,500
- B: 11,800
- C: 12,700
Step-by-step explanation:
Since the number of A seats equals the total of the rest of the seats, it is half the seats in the stadium: 49000/2 = 24,500.
The revenue from those seats is, ...
24,500×$30 = $735,000
so the revenue from B and C seats is ...
$1,246,800 -735,000 = $511,800
__
We can let "b" represent the number of B seats. Then there are 24500-b seats in the C section and the revenue from those two sections is ...
24b +18(24500-b) = 511800
6b = 70,800 . . . . . . . . . . . . . . . subtract 441000, collect terms
b = 70,800/6 = 11,800 . . . . . . . seats in B section
24,500 -11,800 = 12,700 . . . . . seats in C section
There are 24500 seats in Section A, 11800 seats in Section B, and 12700 seats in Section C.
Answer:
Since this is a proportional relationship,
We know that the number which are proportional are a multiple of each other
the number which we can multiply one of the numbers to get the other number is the constant of proportionality
we could check for proportionality by using the following formula:
p1 / s1 = p2/s2 = p3/s3 = p4/s4 if they were equal, we can say that the relation is proportional
The value of any of the above values, p1/s1 , p2/s2 , p3/s3 , p4/s4 is the constant of proportionality
Therefore, the constant of proportionality = 20 / 5 = 4
Answer:
Probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.
Step-by-step explanation:
We are given that a classroom of 20 children in one such area where 13.5% of children are unvaccinated.
If there are no siblings in the classroom, we are willing to consider the vaccination status of the 2020 unrelated children to be independent.
The above situation can be represented through binomial distribution;
where, n = number of trials (samples) taken = 20 children
r = number of success = none of the 20 children
p = probability of success which in our case is probability that
children are unvaccinated, i.e; p = 13.5%
<u><em>Let X = Number of children that are unvaccinated</em></u>
So, X ~ Binom(n = 20, p = 0.135)
Now, Probability that none of the 20 children in such a classroom would be unvaccinated is given by = P(X = 0)
P(X = 0) = 
= 
= 0.055
<em>Hence, the probability that none of the 20 children in such a classroom would be unvaccinated is 0.055.</em>
Answer:
hi, i love matha lthough i would like it if it were in english. merci!
Step-by-step explanation:
okie baii
If you add the numbers 57 and 59 together you get 116
