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beks73 [17]
4 years ago
14

Find 2 consecutive odd integers whose sum is 116

Mathematics
2 answers:
zysi [14]4 years ago
8 0
If you add the numbers 57 and 59 together you get 116
luda_lava [24]4 years ago
5 0
To find the answer using an equation, use x for the first integer, and use x+2 as the second integer. (we add 2 to x because odd numbers are 2 away from each other. You would have to add 2 to an odd number to get the next consecutive odd number).
"sum" means to add, so add the two integers together:
x + x+2 = 116
Combine like terms:
2x + 2 = 116
Subtract 2:
2x = 114
Divide by 2:
x = 57 (first integer)
x+2 = 57+2 = 59 (second integer)
Check: 57+59=116
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6 0
3 years ago
25x^2+9y^2+72y-81=0. Find the standard form of the equation by completing the square. Then identify and graph each conic.
olasank [31]
          25x² + 9y² + 72y - 81 = 0
                   25x² + 9y² + 72y - 81 + 81 = 0 + 81
                                   25x² + 9y² + 72y = 81
                           25x² + 9(y² + 8y + 16) = 81 + 9(16)
                   25x² + 9(y² + 4y + 4y + 16) = 81 + 144
           25x² + 9(y(y) + 4(y) + 4(y) + 4(4)) = 225
                  25x² + 9(y(y + 4) + 4(y + 4)) = 225
                            25x² + 9(y + 4)(y + 4) = 225
                                     <u>25x²</u> + <u>9(y + 4)²</u> = <u>225</u>
                                     225         225       225
                                         <u> x²</u> + <u>9(y + 4)²</u> = 1
                                         25        25

The conic section is an ellipse.
8 0
3 years ago
X + x(x + y) + y; use x = 4, and y = 1
leva [86]

\huge\text{Hey there!}

\huge\text{x + x(x + y) + y}

\huge\text{= 4 + 4(4 + 1) + 1}

\huge\text{= 4 + 4(5) + 1}

\huge\text{= 4 + 20 + 1}

\huge\text{= 24 + 1}

\huge\text{= 25}

\huge\boxed{\textsf{Therefore, your answer is: 25}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\huge\boxed{\frak{Amphitrite1040:)}}

5 0
3 years ago
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