All categories

3 years ago

Given the figure below, find the values of x and z.

Mathematics

1 answer:

ipn [44]3 years ago

4 0

Answer:

<h2>Value of :</h2><h2>x = 12°</h2><h2>z = 101°</h2>

By using the Vertically Opposite Angles  property

79 = 6x + 7 where value we get is x = 12

By using Linear pair  property

79 + z = 180 where we get the value of z = 101

You might be interested in

What equation best represents the following sentence?

nikdorinn [45]

Answer: n + 2 = 2n

Step-by-step explanation:

sum = add

number and two = n, 2

twice the number = 2 x n

4 0

3 years ago

What is the answer to 7x+7 = 3x+9

devlian [24]

Answer:x=1/2

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Write the following fraction as a decimal. 2<img src="https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B10%7D" id="TexFormula1" title

vfiekz [6]

Answer:

2/10 or 1/2 = .5 you would divide 2 by 2 and 10 divided by 2 (whatever you multiply or divide by on the top you must do on the bottom)

2/10=.50

3/100=.03 (divide 3 by 10=.0

5 0

3 years ago

Read 2 more answers

You stand a known distance from the base of the tree, measure the angle of elevation the top of the tree to be 15â—¦ , and then

gogolik [260]

Answer:

The maximum possible error of in measurement of the angle is $d\theta_1 =(14.36p)^o$

Step-by-step explanation:

From the question we are told that

The angle of elevation is $\theta_1 = 15 ^o = \frac{\pi}{12}$

The height of the tree is h

The distance from the base is D

h is mathematically represented as

$h = D tan \theta$ Note : this evaluated using SOHCAHTOA i,e

$tan\theta = \frac{h}{D}$

Generally for small angles the series approximation of $tan \theta \ is$

$tan \theta = \theta + \frac{\theta ^3 }{3}$

So given that $\theta = 15 \ which \ is \ small$

$h = D (\theta + \frac{\theta^3}{3} )$

$dh = D (1 + \theta^2) d\theta$

=> $\frac{dh}{h} = \frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta$

Now from the question the relative error of height should be at most

$\pm p$ %

=> $\frac{dh}{h} = \pm p$

=> $\frac{1 + \theta ^2}{\theta + \frac{\theta^3}{3} } d \theta = \pm p$

=> $d\theta = \pm \frac{\theta + \frac{\theta^3}{3} }{1+ \theta ^2} * \ p$

So for $\theta_1$

$d\theta_1 = \pm \frac{\theta_1 + \frac{\theta^3_1 }{3} }{1+ \theta_1 ^2} * \ p$

substituting values

$d [\frac{\pi}{12} ] = \pm \frac{[\frac{\pi}{12} ] + \frac{[\frac{\pi}{12} ]^3 }{3} }{1+ [\frac{\pi}{12} ] ^2} * \ p$

=> $d\theta_1 = 0.25 p$

Converting to degree

$d\theta_1 = (0.25* 57.29) p$

$d\theta_1 =(14.36p)^o$

4 0

3 years ago

How do you interpret the residual?

Vanyuwa [196]

Answer: To find a residual you must take the predicted value and subtract it from the measured value.

Step-by-step explanation:

7 0

3 years ago