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Vaselesa [24]
2 years ago
14

Simplify2

Formula1" title=" \s \sqrt{x { } ^{2} -4x + 4} " alt=" \s \sqrt{x { } ^{2} -4x + 4} " align="absmiddle" class="latex-formula">
x^2 - 4x + 4 if x<2​
Mathematics
2 answers:
deff fn [24]2 years ago
5 0

Answer:

2 - x

Step-by-step explanation:

x² - 4x + 4

4 = (-2)*(-2)

- 4 = -2 -2

x² - 4x + 4  = (x - 2)(x - 2) = (x - 2)²

√[(x - 2)²] = |x - 2|

or abs(x-2) because value under the root should be positive

if x< 2, then |x-2| = -(x-2) = 2 -x

3241004551 [841]2 years ago
4 0

Answer:

2-x

Step-by-step explanation:

Vx^2-4x+4=Vx^2-2*x*2+2^2=V(x-2)^2=|x-2|

if x<2 then x-2<0 and |x-2|=2-x

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3 years ago
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Step-by-step explanation:

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3 0
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Step-by-step explanation:

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3 years ago
Can Someone PLEASE help me <br> And if you can show your work.
Setler79 [48]
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3 years ago
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Answer:

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Subtract 6 from each side

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n = 15

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