Simplify2

Question

3 years ago

14

Formula1" title=" \s \sqrt{x { } ^{2} -4x + 4} " alt=" \s \sqrt{x { } ^{2} -4x + 4} " align="absmiddle" class="latex-formula">
x^2 - 4x + 4 if x<2

2 answers:

deff fn [24] · Answer 1 · 2022-08-07T18:38:45+03:00

5 0

Answer:

2 - x

Step-by-step explanation:

x² - 4x + 4

4 = (-2)*(-2)

- 4 = -2 -2

x² - 4x + 4 = (x - 2)(x - 2) = (x - 2)²

√[(x - 2)²] = |x - 2|

or abs(x-2) because value under the root should be positive

if x< 2, then |x-2| = -(x-2) = 2 -x

3241004551 [841] · Answer 2 · 2022-08-07T20:05:45+03:00

4 0

Answer:

2-x

Step-by-step explanation:

Vx^2-4x+4=Vx^2-2*x*2+2^2=V(x-2)^2=|x-2|

if x<2 then x-2<0 and |x-2|=2-x