Simplify2
Formula1" title=" \s \sqrt{x { } ^{2} -4x + 4} " alt=" \s \sqrt{x { } ^{2} -4x + 4} " align="absmiddle" class="latex-formula">
x^2 - 4x + 4 if x<2
2 answers:
Answer:
2 - x
Step-by-step explanation:
x² - 4x + 4
4 = (-2)*(-2)
- 4 = -2 -2
x² - 4x + 4 = (x - 2)(x - 2) = (x - 2)²
√[(x - 2)²] = |x - 2|
or abs(x-2) because value under the root should be positive
if x< 2, then |x-2| = -(x-2) = 2 -x
Answer:
2-x
Step-by-step explanation:
Vx^2-4x+4=Vx^2-2*x*2+2^2=V(x-2)^2=|x-2|
if x<2 then x-2<0 and |x-2|=2-x
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