All categories

3 years ago

Plz help me well mark brainliest if correct.........?

Mathematics

1 answer:

TiliK225 [7]3 years ago

7 0

Answer:

The answer is B

Step-by-step explanation:

8 times 12 = 96

2L + 2W = 40

2(8) + 2(12) = 40

because

16 + 24 = 40

Hope this helps!

You might be interested in

Write 38/15 as a mixed number

MrMuchimi

2 8/15 is the answer

7 0

3 years ago

Read 2 more answers

What is the value of Y in the exponential decay function when x equals 3? Y=0.25x

Taya2010 [7]

Plug three in wherever there is an x
y=.25(3)
y=.75

7 0

3 years ago

Read 2 more answers

. A ball is thrown upward. Its height (h, in feet) is

Fudgin [204]

Answer:

Well none of the answers are correct as maximum height is found by doing -b/2a which gives the x coordinate of the vertex also known as the heighest or lowest point. But when plugged in it gives the lowest point assuming you made the mistake of making the 16 positive when its supposed to be negative you would plug it in and get 98 which isn't an answer choice assuming 34 is the ground when you subtract that you get 64 whch still isn't an answer choice check your numbers in the equation

8 0

3 years ago

Read 2 more answers

If you ate half of the servings in this container, how many calories would you have consumed?

Elan Coil [88]

Answer:

230(1/2)= 115

920(1/2)= 460

460(1/2)= 230

1840(1/2)= 920

5 0

3 years ago

Read 2 more answers

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago